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Thepotemich [5.8K]
3 years ago
11

Solving Rational equations. LCD method. Show work. Image attached.

Mathematics
1 answer:
Ugo [173]3 years ago
5 0

Answer:

k=\frac{1}{2}

Step-by-step explanation:

The given rational equation is

\frac{5k}{k+2}+\frac{2}{k}=5

The Least Common Denominator is

k(k+2)

Multiply each term by the LCD.

k(k+2)\times \frac{5k}{k+2}+k(k+2)\times \frac{2}{k}=5k(k+2)

Simplify;

k\times \frac{5k}{1}+(k+2)\times \frac{2}{1}=5k(k+2)

\Rightarrow k(5k)+2(k+2)=5k(k+2)

Expand;

\Rightarrow 5k^2+2k+4=5k^2+10k

Group similar terms;

\Rightarrow 5k^2-5k^2+2k-10k=-4

\Rightarrow -8k=-4

Divide by -8.

k=\frac{1}{2}

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A sheet of drywall is cut into quarters. Each quarter is cut into thirds. What fraction of a whole sheet is each of these small
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X/12

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Read 2 more answers
Express sin A, cos A, and tan A as ratios ​
vlabodo [156]
<h3>Answer: Choice B</h3><h3>sqrt(3)/2,    1/2,   sqrt(3)</h3>

================================================

Explanation:

Sine of an angle is the ratio of the opposite side over the hypotenuse. For reference angle A, the opposite side is BC = 6sqrt(3). The hypotenuse is the longest side AB = 12

Sin(angle) = opposite/hypotenuse

sin(A) = BC/AB

sin(A) = 6sqrt(3)/12

sin(A) = sqrt(3)/2

---------------

Cosine is the ratio of the adjacent and hypotenuse

cos(angle) = adjacent/hypotenuse

cos(A) = AC/AB

cos(A) = 6/12

cos(A) = 1/2

---------------

Tangent is the ratio of the opposite and adjacent

tan(angle) = opposite/adjacent

tan(A) = BC/AC

tan(A) = 6sqrt(3)/6

tan(A) = sqrt(3)

5 0
3 years ago
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