-2x^2-20x-46 How would you solve this?
1 answer:
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Answer:
5g of norgestel are used in making 10,000 tablets.
0.5g of ethinyl estradiol are used in making 10,000 tablets.
Step-by-step explanation:
This problem can be solved as a rule of three problem.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
Unit conversion problems, like this one, is an example of a direct relationship between measures.
First step: Grams of norgestrel
Each tablet contais 0.5mg of norgestrel. How many miligrams are in 10,000 tablets?
1 tablet - 0.5 mg
10,000 tablets - x mg
x = 10,000*0.5
x = 5,000 mg
Now we have to convert 5,000 mg to g. Each g has 1,000 mg. So:
1g - 1,000 mg
xg - 5,000 mg
1,000x = 5,000
x = 5g,
5g of norgestel are used in making 10,000 tablets.
Final step: Grams of ethinyl estradiol
50ug = 0.05 mg.
So
1 tablet - 0.05mg
10,000 tablets - xg
x = 10,000*0.05
x = 500 g
Now we have to convert 500 mg to g. Each g has 1,000 mg. So:
1g - 1,000 mg
xg - 500 mg
1,000x = 500
x = 0.5g,
0.5g of ethinyl estradiol are used in making 10,000 tablets.
Answer:
Step-by-step explanation:
The summary of the given data includes;
sample size for the first school = 42
sample size for the second school = 34
so 16 out of 42 i.e = 16 and 18 out of 34 i.e
= 18 have ear infection.
the proportion of students with ear infection Is as follows:
= 0.38095
= 0.5294
Since this is a two tailed test , the null and the alternative hypothesis can be computed as :
level of significance ∝ = 0.05,
Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.
The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.
The pooled standard error can be computed by using the formula:
The test statistics is ;
z = - 1.368
Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.
Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools