X + 3 = 0
2x - 1 = 0
It would be D.
Answer:
Linear function 2x+3y=12 .
Step-by-step explanation:
To find y-intercept , make x=0 :
3y = 12
y = 12/3
y = 4 .
To find x-intercept , make y=0 :
2x = 12
x = 12/2
x = 6 .
<u> ! Hope this will help you !</u>
Answer:
Option D. ![\sqrt[4]{\frac{3x^{2}}{2y}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E%7B2%7D%7D%7B2y%7D%7D)
Step-by-step explanation:
![\sqrt[4]{\frac{24x^{6}y}{128x^{4}y^{5}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E%7B6%7Dy%7D%7B128x%5E%7B4%7Dy%5E%7B5%7D%7D%7D)
![\sqrt[4]{(\frac{24}{128})\times (\frac{x^{6}}{x^{4}})\times (\frac{y}{y^{5}})}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B24%7D%7B128%7D%29%5Ctimes%20%28%5Cfrac%7Bx%5E%7B6%7D%7D%7Bx%5E%7B4%7D%7D%29%5Ctimes%20%28%5Cfrac%7By%7D%7By%5E%7B5%7D%7D%29%7D)
= ![\sqrt[4]{(\frac{3}{16})\times {(x)^{6-4}}\times{(y)^{1-5}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B3%7D%7B16%7D%29%5Ctimes%20%7B%28x%29%5E%7B6-4%7D%7D%5Ctimes%7B%28y%29%5E%7B1-5%7D%7D%7D)
= ![\sqrt[4]{(\frac{3}{16})\times x^{2}y^{-4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28%5Cfrac%7B3%7D%7B16%7D%29%5Ctimes%20x%5E%7B2%7Dy%5E%7B-4%7D%7D)
= ![\sqrt[4]{\frac{3}{(2)^{4}}\times x\times y^{-4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3%7D%7B%282%29%5E%7B4%7D%7D%5Ctimes%20x%5Ctimes%20y%5E%7B-4%7D%7D)
= ![\sqrt[4]{(3\times x^{2)\times (\frac{y^{-1}}{2})^{4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%283%5Ctimes%20x%5E%7B2%29%5Ctimes%20%28%5Cfrac%7By%5E%7B-1%7D%7D%7B2%7D%29%5E%7B4%7D%7D%7D)
= ![\frac{y^{-1}}{2}\sqrt[4]{3x^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7By%5E%7B-1%7D%7D%7B2%7D%5Csqrt%5B4%5D%7B3x%5E%7B2%7D%7D)
=
Option D. is the correct answer.
The value is -ayre la lute
Answer:
<u><em>(x+2)^2 + (y-6)^2 = 41</em></u>
Step-by-step explanation:
The equation for a circle is (x-h)^2+(y-k)^2=r^2
So first, it is known that the circle's center is at (-2,6), Therefore, this can be filled in:
(x+2)^2+(y-6)^2=r^2
Next, we need to find the radius, and one of the points is already known, being (-6, 1)
With this, find the distance between these two points by doing the Pythagorean Theorem, a^2+b^2=c^2. The a^2 would be the x value changed and the b^2 would be the y value changed between the two numbers. Note that this is interchangeable.
To find a:
-2 to -6 = change of 4
To find b:
6 to 1 = change of 5
Next, write out the equation for this:
4^2+5^2=c^2
16+25=c^2
41=c^2
c = √41
The radius would be √41, so the equation can now be completed. Since c will be brought to the second power, this will cancel out the square root.
(x+2)^2 + (y-6)^2 = 41
Hope that helps.
