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lbvjy [14]
3 years ago
13

PLEASE IS FOR MY HOMEWORK

Mathematics
1 answer:
Neporo4naja [7]3 years ago
6 0

a. 7x + 52 (2x + 5x) (40 + 12)

b. 13x + 142 (2x+5x+6x) (40 + 12 - 10)

c. 246 (16 + 40 + 40 + 100 + 12 + 48 - 10)

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y = mx + b

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Use that form to find the slope.

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Are 2/3×3/8 is greater than 3/8 or less than 3/8
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If the midpoint of A (a, b) and B(-9, 6) is M(-3, 5):<br> Find the value of a.
WINSTONCH [101]

Answer:

\huge{ \fbox{ \text{3}}}

Step-by-step explanation:

\sf{A ( \: a \:, b \: )\:  \longrightarrow{ \: (x1 \:, y1)}}

\sf{ \: B( - 9 \: 6) \:  \longrightarrow{ (x2 \:, y2)}}

\boxed{ \sf{midpoint = ( \frac{x1 + x2}{2}  \: , \frac{y1 + y2}{2} )}}

\mapsto{ \sf{( - 3 \:, 5 \: ) \:  =  \: ( \frac{a + ( - 9)}{2}  \:,  \frac{b + 6}{2}}})

\mapsto{ \sf{( - 3 \:, 5) \:  =  \: ( \:  \frac{a  - 9}{2}  \:,  \frac{b + 6}{2} )}}

\sf{  \mapsto{ - 3 =  \frac{a - 9}{2} }}

Solve for a

\mapsto{ \sf{ - 6 = a - 9}}

\mapsto{ \sf{a - 9 =  - 6}}

\mapsto{ \sf{a =  - 6 + 9}}

\mapsto{ \sf{a = 3}}

The value of a is 3

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

7 0
4 years ago
Read 2 more answers
Determine if the equation x^2 + 3y^2= 3 defines y as a function of x
belka [17]

Answer:

y is NOT a function.

Step-by-step explanation:

The equation given to us is:

x² + 3y² = 3

Rearrange the equation:

3y² = 3 - x²

y² = (3 - x²)/3

y² = 1 - (x²)/3

y = ±√(1 - x²/3)

For any equation to be a function, there should be only one output for one input. Which means that for any value of x, there should be only one value of y. However, in this equation, as the underroot gives two values of any terms under it, it shows that if we put any value of x, we'll get 2 values of y. Therefore, y is not a function.

4 0
3 years ago
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