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Ber [7]
3 years ago
9

Bianca calculated the height of the equilateral triangle with side lengths of 10. Then, she used the formula for area of a trian

gle to approximate its area, as shown below. Calculate the area of the equilateral triangle using the formula for area of a regular polygon, and compare it to Bianca’s answer. The apothem, rounded to the nearest tenth, is ---units. The perimeter of the equilateral triangle is ---units. Therefore, the area of the equilateral triangle is---- , or approximately 43.5 units2. The calculated areas are---
Mathematics
2 answers:
tekilochka [14]3 years ago
6 0
2.9
30
1/2(2.9)30
the same. despite different formulas.
give me brainliest pls
DanielleElmas [232]3 years ago
5 0

Answer:

1) - A. 2.3

2) - C. 30

3) - A. 1/2(2.9)(30)

4) - D. The same, despite using different formulas.

Just took quiz.

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A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
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Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

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Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

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