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nadezda [96]
3 years ago
8

I have nothing to add here lolololol

Mathematics
1 answer:
Fynjy0 [20]3 years ago
7 0
X= 20
4X= 100
mark me as brainliest !
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Henry ran five races, each of which was a different positive integer number of
dolphi86 [110]

Answer:

10 miles.

Step-by-step explanation:

Let x be the number of miles on Henry's longest race.

We have been given that Henry ran five races, each of which was a different positive integer number of  miles.

We can set an equation for the average of races as:

\frac{\text{The sum distances of 5 races}}{5}=4

As distance covered in each race is a different positive integer, so let his first four races be 1, 2, 3, 4.

Now let us substitute the distances of 5 races as:

\frac{1+2+3+4+x}{5}=4

\frac{10+x}{5}=4

Let us multiply both sides of our equation by 5.

\frac{10+x}{5}*5=4*5

10+x=20

Let us subtract 10 from both sides of our equation.

10-10+x=20-10

x=10

Therefore, the maximum possible distance of Henry's longest race is 10 miles.

7 0
3 years ago
What are the x and y-intercepts of the line described by the equation?
KiRa [710]

Answer:

x-int (6.2, 0)

y-int (0, 3.1)

Step-by-step explanation:

x-intercept is found when y = 0.

y-intercept is found when x = 0.

Step 1: Define equation

2x + 4y = 12.4

Step 2: Find x-intercept

<em>Substitute y for 0.</em>

2x + 4(0) = 12.4

2x = 12.4

x = 6.2

(6.2, 0)

Step 3: Find y-intercept

<em>Substitute x for 0.</em>

2(0) + 4y = 12.4

4y = 12.4

y = 3.1

(0, 3.1)

6 0
3 years ago
anyone know the answer i worked it out but didn't know where i messed up so i am just gonna ask for someone to help me with it.
hram777 [196]
I also worked it out but I got -5/3

2(6p-5) ≥ 3(p-8) -1

12p-10 ≥ 3p-24-1

12p-10 ≥ 3p-25

12p-3p ≥ -25+10

9p ≥ -15

-15/9

P ≥ -5/3
5 0
3 years ago
A concert ticket that originally cost $46.50 is on sale for $38.75. What is the percent of decrease, rounded to the nearest tent
Arturiano [62]
You subtract 38.75 from 46.5, which is 7.75. 7.75/46.5=about .16666, or 16.7 percent.
5 0
3 years ago
PLEASE! ANSWER THIS! HELP! PLEASE!!!!!!!!!!!!!! <br><br>c. Expand: (tan(theta) - 1)^3​
jonny [76]

Answer:

(tan(theta)-1)^3

= (tan(theta)-1)(tan(theta)-1)(tan(theta)-1)

= (tan^2(theta)-2tan(theta)+1)(tan(theta)-1)

= tan^3(theta)-2tan^2(theta)+tan(theta)-tan^2(theta)+2tan(theta)-1

= tan^3(theta)-3tan^2(theta)+3tan(theta)-1

Hope this helps :)

6 0
2 years ago
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