All categories

3 years ago

What is the simplified form of the quantity y−squared minus y minus 12 over the quantity y−squared plus 8y plus 15?

Mathematics

1 answer:

kkurt [141]3 years ago

6 0

Y^2-y-12/y^2+8y+15=

(y-4)(y+3)/(y+3)(y+5)=

The y+3 cancel out. Therefore: (y-4)/(y+5)

You might be interested in

80,531 rounded to nearest thousand

Vlad [161]

Answer:

81,000

Step-by-step explanation:

go to whatever place it is asking you to round nearest to the if it is 5 or more you round up 4 or less it stays the same.

Saying for this -" 5 or more raise the score, 4 or less let it rest"

^round up^ ^stays the same^

4 0

3 years ago

Read 2 more answers

Persons younger than 18 years old are not eligible to vote. Let a be age in years.

BaLLatris [955]

D because a has to be younger than 18 and it has to be positive because we are never a negative age. do you understand when i mean?
<span />

3 0

3 years ago

Read 2 more answers

10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135

Viefleur [7K]

The simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .

First we must simplify the expression:
$\frac{3 \sqrt{160} }{\sqrt{1350x} } = \frac{12 \sqrt{10} }{15 \sqrt{6x} } = \frac{4 \sqrt{10} }{5 \sqrt{6x} }$

Then we factor the rational parts and cancel it out:
$\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }$

Then we rationalize the expression:
$\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}$

<span>Finally, the simplified expression by rationalizing the denominator is (C) $\frac{4 \sqrt{15x} }{15x}$ .</span>

7 0

3 years ago

85,109,178 in world form

igor_vitrenko [27]

Eighty five million, one hundred nine thousand, one hundred seventy-eight.

5 0

3 years ago

The solution set of the equation Ix-1I=3 is

vladimir2022 [97]

Answer:

x = - 2 or x = 4

Step-by-step explanation:

the expression inside the absolute value can be positive or negative

Removing the bars and solve x - 1 = ± 3

x - 1 = - 3 or x - 1 = 3

x - 1 = - 3 ( add 1 to both sides ) ⇒ x = - 2

x - 1 = 3 ( add 1 to both sides ) ⇒ x = 4

7 0

3 years ago