The solution would be like
this for this specific problem:
<span>V = ∫ dV </span><span>
<span>= ∫0→2 ∫
0→π/2 ∫ 0→ 2·r·sin(φ) [ r ] dzdφdr </span>
<span>= ∫0→2 ∫
0→π/2 [ r·2·r·sin(φ) - r·0 ] dφdr </span>
<span>= ∫0→2 ∫
0→π/2 [ 2·r²·sin(φ) ] dφdr </span>
<span>= ∫0→2 [
-2·r²·cos(π/2) + 2·r²·cos(0) ] dr </span>
<span>= ∫0→2 [
2·r² ] dr </span>
<span>=
(2/3)·2³ - (2/3)·0³ </span>
<span>= 16/3 </span></span>
So the volume of the
given solid is 16/3. I am hoping that these answers have satisfied
your query and it will be able to help you in your endeavors, and if you would
like, feel free to ask another question.
Answer:
3.
Step-by-step explanation:
Implicit differentiation:
x^2 y + (xy)^3 + 3x = 0
x^2 y + x^3y^3 + 3x = 0
Using the product rule:
2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0
2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0
dy/dx(x^2 + 3y^2x^3) = (-2xy - 3x^2y^3 - 3)
dy/dx= (-2xy - 3x^2y^3 - 3) / (x^2 + 3y^2x^3)
At the point (-1, 3).
the derivative = (6 - 81 - 3)/(1 -27)
= -78/-26
= 3.
Let n be a number of friends at the perty. If <span>dinner costs $30 per person, then it cost $30n for all friends.
</span>
Robert has booked a banquet hall which costs <span>$200, then his total expenses are $200+30n.
</span>
If the final bill is p, then p=<span>200+30n.
</span>
Answer: p=<span>200+30n.</span>
Step-by-step explanation:
So 95 is a linear pair. a linear pair adds up to 180 so 180 - 95 = 85
X = 85
y = 50
