Answer:
A) x ≤ -2 and 0 ≤ x ≤ 3
Step-by-step explanation:
g(x) is decreasing when g'(x) is negative.
Use second fundamental theorem of calculus to find g'(x).
g(x) = ∫₋₁ˣ (t³ − t² − 6t) / √(t² + 7) dt
g'(x) = (x³ − x² − 6x) / √(x² + 7) (1)
To find when g'(x) is negative, first find where it is 0.
0 = (x³ − x² − 6x) / √(x² + 7)
0 = x³ − x² − 6x
0 = x (x² − x − 6)
0 = x (x − 3) (x + 2)
x = -2, 0, or 3
Check the intervals before and after each zero.
x < -2, g'(x) < 0
-2 < x < 0, g'(x) > 0
0 < x < 3, g'(x) < 0
3 < x, g'(x) > 0
g(x) is decreasing on the intervals x ≤ -2 and 0 ≤ x ≤ 3.
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<h2>D. If subjects knew they were receiving an active treatment, researchers would not have known if any improvement was due to the new medication or to the expectation of <u>feeling </u>better. If the researchers knew which subjects received which treatments, they might have treated one group of subjects differently from the other group.</h2><h2 />
For your question... the answer would be D
Answer:
1. y = 9280 - 20x
2. f(y) = 6.37y - 3
Step-by-step explanation:
1. The equation is given to be 
Now, rearranging the function we can write
⇒ y = 9280 - 20x
Hence, this is the equation as a function of x. (Answer)
2. The given function is y - 6.37x = - 3
Therefore, we can write, y = 6.37x - 3
Hence, f(x) = 6.37x - 3
⇒ f(y) = 6.37y - 3.
Hence, option D is true. (Answer)
Alright, lets get started.
Please take a look to the diagram I have attached.
The base side is ON
The terminal side is MN.
We could say angle MNO as angle N.
We could day it as angle ONM also.
So, the answer is ∠ N and ∠ONM. : Answer
Hope it will help :)
