Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
Answer:
the slope is 5
Step-by-step explanation:
f(x) = 5x
f(8) = 5(8) = 40 (8,40)
f(7) = 5*7 = 35 ( 7,35)
the slope is 5
it is from the range of 6<x<26. I hope this helps. Could I possibly get brainliest?
Here is the answer all you have to do is go 1984 divide by 42 47.23809524
The answer would be 6 I think
