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Vilka [71]
3 years ago
6

Select the correct text in the table. Use the fundamental theorem of algebra to determine whether each statement is sometimes tr

ue, always true, or never true.
1. A quadratic function has 2 distinct roots. always sometimes never
2. A cubic function has at least 1 real root. always sometimes never
3. A function with a degree of 5 has 5 roots. always sometimes never

4. A quadratic function can have only 1 complex solution. always sometimes never
Mathematics
2 answers:
Mariana [72]3 years ago
6 0

Answer:

MY ANSWER IS CORRECT IN PLATO!!!

1. Sometimes

2. Always

3. Always

4. Never

Step-by-step explanation:

1. A quadratic function has 2 distinct roots SOMETIMES

2. A cubic Function has at least 1 root ALWAYS

3. A function with a degree of 5 has 5 roots ALWAYS

4. A quadratic function can have only 1 complex solution NEVER

I JUST GOT 100% on the quiz in PLATO

yan [13]3 years ago
5 0

Answer:

1. Sometimes

2. Sometimes

3. Always

4. Sometimes

Step-by-step explanation:

1. Quadratic function : in which maximum power of x is two.

The roots of quadratic function can be either equal or different.

For example:

  • x^{2} -2x+1 will have two equal roots i.e. 1 and 1.
  • x^{2} -3x+2 will have two different roots i.e. 1 and 2.

So, <em>sometimes </em>is the correct answer.

2. Cubic function has atleast 1 real root.

Cubic function has maximum power of x as 3.

If the coefficients are real numbers then atleast 1 real root.

If the coefficients are imaginary in nature, then this is not true.

For example:

Cubic equation x^3 +i = 0 does not have any real root.

Cubic equation x^3 +1 = 0 has a real root x = -1.

So, it is sometimes true.

3. A function with degree 5 i.e. maximum power of x as 5 will have 5 roots.

It is always true that a function will have number of roots equal to its degree.

4. Quadratic function can have only 1 complex solution.

Two complex solutions are also possible for a quadratic function.

For example:

x^{2} +1=0 will have two imaginary roots: x=i, -i

It is also possible to have 1 complex solution,

For example:

(x-1)(x-i) = 0 will have one complex root and one real root.

So, the statement is <em>sometimes </em>true.

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2 years ago
How many solutions does the system have?
amid [387]

Answer:

A; infinitely many solutions

Step-by-step explanation:

first, let's simplify the first equation to make it simpler.

divide both sides by 5

y=3x-8

new system

y=3x-8

y=3x-8

as you can see, they are the same.

not mandatory but useful!⬇⬇⬇⬇

just to be more clear, let's substitute them. since they're both already in y=, we can make them both set to each other.

3x-8=3x-8

add 8 to both sides; subtract 3x from one side

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8 0
3 years ago
Expand the binomial (2x^2+y^2)^4. Fill in the missing coefficients in the expansion of the binomial .
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5 0
3 years ago
Please answer this question only if you know the answer! 30 points and brainliest!
Allisa [31]

Answer:

(4, 3)

Step-by-step explanation:

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A': (4, 3)

5 0
3 years ago
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Nastasia [14]

Answer:

A. g(x) = -2^x.

Step-by-step explanation:

If g(x) = -2, it would be a straight line running horizontally.

If g(x) = -x, it would be a linear equation.

If g(x) = -|x|, it would be an absolute value function, which is a graph in a v-shape.

So, the remaining answer is that A. g(x) = -2^x.

Hope this helps!

3 0
3 years ago
Read 2 more answers
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