To find the value of x² + (2y) ÷(2w) +3z , first we substitute the values of w, x, y and z
5² + 2(8) ÷ 2(2) + 3(3)
To simplify this further, we have to apply the rule of BODMAS
(Applying the rule of BODMAS simply means when you have an equation, if its having bracket, you have to remove the bracket first, then you move to powers then you proceed to dividing then subtraction and then addition)
5² + 2(8) ÷ 2(2) + 3(3)
=25 +16 ÷ 4 +9
=25 + 4 +9
=38
Therefore the value of x² + (2y) ÷(2w) +3z is 38
Answer:
4(4y+5k)
Step-by-step explanation:
if you do 4 x 4y thats 16y and 4 x 5k is 20k \
pls give brainliest
Answer:
Step-by-step explanation:
Just multiply the two sides
1. 
Use FOIL (First, Outer, Inner, Last)
2.
^ After simplifying
In PEMDAS, there is no parentheses in this equation, so we move on to exponents.
-5^2 is 25
Now, we divide -15/-3 then we get 5
Next, we do -3+20=17
25+5+17 would be 47
Your answer should be 47!
Hope this helps (:
