X = y + 12. You then substitute or plug in that from the first equation into the second equation. You get (y+12)+y=18, then you simplify to get your y value. In this case y = 3. The you can plug your y value into either equation. (x+3=18) or (x-3=12) or (x=3+12) either way you get x=15 and y=3.
Answer:
answer A : (2 -5)
Step-by-step explanation:
the midipoint P,Q is the center A of this circle (because PQ is a diameter)
use : (x-6)²+(x+5)² = 16 you have : A(6 , -5) now let Q(x,y) :
(x+10)/2 = 6
(y-5)/2 = - 5
x+10 = 12
y-5 = -10
so : x = 2 and y = - 5....answer A : (2 -5)
The first five terms of the sequence are; 4,600, 4,550, 4,500, 4,450, 4,400 and the total predicted number of sold cars for the first year is 51,900 cars
<h3>Arithmetic sequence</h3>
- First month, a = 4,600 cars
- Common difference, d = -50 cars
First five terms;
a = 4,600
a + d = 4600 + (-50)
= 4600 - 50
= 4,550
a + 2d
= 4600 + 2(-50)
= 4600 - 100
= 4,500
a + 3d
= 4,600 + 3(-50)
= 4,600 - 150
= 4,450
a + 4d
= 4600 + 4(-50)
= 4,600 - 200
= 4,400
cars predicted for the twelfth month.
a + 11d
= 4600 + 11(-50)
= 4600 + 550
= 4,050
Total predicted number of sold cars for the first year:
Sn = n/2{2a + (n - 1)d }
= 12/2{2×4600 + (12-1)-50}
= 6{9200 + 11(-50)}
= 6(9,200 - 550)
= 6(8,650)
= 51,900 cars
Learn more about arithmetic sequence:
brainly.com/question/6561461
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Answer:
unreadable score = 35
Step-by-step explanation:
We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".
There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":
1) The mean score of ALL exams (including the unreadable one) is 80
so the equation to represent this statement is:
mean of ALL exams = 80
By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:
since the mean is the addition of all values divided the total number of exams.
in a similar way we can write what the mean of just the readable exams is:
(notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.
Based on the equation above, we can find what "R" is by multiplying both sides by 9:
Therefore we can now use this value of R in the very first equation we created, and solve for "x":
Answer:
Step-by-step explanation:
We are given that
We have to find 
To find the value of we will multiply f(x) by g(y)
Now,
Hence,
