Help me please, thank you.

I do no understand this

vovangra [49]

The equation of a line for the given slope is $y=\frac{1}{2} x+1$ .

Solution:

Given data:

Slope (m) = $\frac{1}{2}$

Point = (–2, 0)

$x_1=-2, y_1=0$

To find the equation of the given line in the point-slope form:

<u>Point-slope formula:</u>

$y-y_1=m(x-x_1)$

Substitute the given values in the formula.

$$y-0=\frac{1}{2} (x-(-2))$

$$y=\frac{1}{2} (x+2)$

$$y=\frac{1}{2} x+\frac{2}{2}$

$$y=\frac{1}{2} x+1$

The equation of a line for the given slope is $y=\frac{1}{2} x+1$ .

5 0

3 years ago

FIRST PERSON TO ANSWER GETS BRAINLIEST OR FIVE STARS Define the domain and range of the function.

uysha [10]

Answer:

Domain: (-∞, ∞)

Range: (-∞, ∞)

Step-by-step explanation:

The domain are the x-values included in the function (the horizontal axis).

The range are the y-values included in the function (the vertical axis).

The two arrows on the ends of the line (pointing upwards and downwards respectively) indicate that the function goes in those direction for infinity. Therefore, if there are an infinite amount of y-values, the range is (-∞, ∞).

While the slope is quite steep, there is still a slope and slowly "expands" the line on the horizontal axis. Because there is no limit to the y-values, the domain will also expand infinitely. Therefore, the domain is also (-∞, ∞).

7 0

2 years ago

Read 2 more answers

If sin A= 0.8, find the positive value of cos A

Ahat [919]

Answer:

cosA = 0.6

Step-by-step explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract sin²A from both sides )

cos²A = 1 - sin²A ( take the square root of both sides )

cosA = ± $\sqrt{1-sin^2A$