Arcsin x + arcsin 2x = π/3
arcsin 2x = π/3 - arcsin x
sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)
2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)
2x = √3/2 . cos(arcsin x) - (1/2)x)
but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²) - (1/2)x)
Reduce to same denominator:
(4x) = √3 .√(1-x²) - (x)===>5x = √3 .√(1-x²)
Square both sides==> 25x²=3(1-x²)
28 x² = 3 & x² = 3/28 & x =√(3/28)
Answer:
angle t is 55 degrees
Step-by-step explanation:
Here's my work:
Isoscelese means two of the same length sides. A triangle is 180 degrees. 180-70=110
110/2=55 (two because those are the two angles associated with the equal sides)
Area of the triangle base: (1/2)*3.3*x
area of the cone base: pi*3*3
they are equal, so 9pi=(1/2)*3.3x
x=17.1
Answer:
Answer below
Step-by-step explanation:
Point D: (-6,-1)
Point C: (-3,0)
Point B: (-3,6)
Point A: (0,0)
