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NemiM [27]
3 years ago
6

If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components a

re drawn at random from the container, the probability that exactly 3 of them are defective is
Mathematics
1 answer:
sammy [17]3 years ago
4 0
There is some inforrmation that is missing in this question. It should read:

<span><span>A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .

</span><u>Answers</u>
<span>Part 1.   0.02
Part 2.  </span></span>0.0375<span><span>

</span><u>Explanation</u>
The probability is a chance of an event happening. It is calculated as;
probability = (Number of favourable outcome)/(Number of available outcome)

Part 1
6 are chosen at random. If 4 are not defective, then 2 are defective.
P(at least 4 are not defective) = 4/40 </span>× 2/10
                                                = 1/10 ×1/5
                                                = 1/50
                                                 = 0.02

Part 2
8 are chosen at random. If 3 are defective, the 5 are not defective. 
P(3 are defective) = 3/40 × 5/10 
                             = 15/400
                             = 3/80
                            = 0.0375
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