The domain of given function is <u>All real numbers</u>
For each value of x the function is defined.
Example -
The value is 
The value is 4
Step-by-step explanation:
We can break this up into pieces, first we do, 7/8 - 1/4, find the least common denominator which is 8, so the equation will be 7/8 - 2/8, which we can now subtract and will give us, 5/8, now that we have done that, we can do 5/8 - 1/2. Since we know that half of 8 (our denominator) is 4. Then the equation would be 5/8 - 4/8, which brings us to 1/8 as our final answer.
Cheers!
Dime value: $0.10
Nickel value: $0.05
For this word problem, you are asked to create an algebraic expression (an equation) for the unknown variables.
Now, we know that a dime is worth $0.10 or 10 cents and a nickel is worth $0.05 or 5 cents. So, all you would have to do is create an equation that takes those values into account.
5n + 10d
Your algebraic expression would be B. 5n + 10d
I hope this helps!
Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
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In many cases, it is preferred to keep the power inside the radical symbol.
