Answer:
x=-1 and y=4
Step-by-step explanation:
y=-3x+1
2x+5y=18
Put x and y on the same side for 1st equation
3x+y=1
2x+5y=18
Multiply top by -5
-15x-5y=-5
2x+5y=18
Add both equations onto each other
-13x=13
x=-1
Plug x=1 into any equation used
2(-1)+5y=18
-2+5y=18
5y=20
y=4
The correct answer is C.
Hope this helps
Because 13 is a prime number, we cannot use the AC method to simplify.
We can instead use the quadratic formula.

11 +/- √121 - 52 / 2
11 +/- √69 / 2
11 +/- 8.3 / 2
(11 + 8.3)/2 = 9.65
(11 - 8.3)/2 = 1.35
<h3>The roots of the polynomial are 9.65 and 1.35.</h3>
Answer:
The probability that at least two homeowners will set their switches to the same code is 100%.
Step-by-step explanation:
Consider the provided information.
The total number of code can be set with 0 or 1 is:
2×2×2×2×2×2×2=128
There are 128 different codes.
The probability that code is unique is 1/128
Now, the probability that all codes are unique is:
![[\frac{1}{128}]^{150}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B128%7D%5D%5E%7B150%7D)
Hence, the probability that all the codes are not unique is:
![1-[\frac{1}{128}]^{150} \approx 1](https://tex.z-dn.net/?f=1-%5B%5Cfrac%7B1%7D%7B128%7D%5D%5E%7B150%7D%20%5Capprox%201)
Because the value of
is very small
As they can set 128 different codes and there are 150 homes. So, at least two homeowners will set their switches to the same code is 100%.
Hence, the probability that at least two homeowners will set their switches to the same code is 100%.
Data on first test: 50, 50, 50, 50, 50
Mean = 250 / 5 = 50
In the next test, Data is: 50, 50, 50, 50, 100
Mean = sum of data / number of data
Mean = 50 + 50 + 50 + 50 + 100 / 5
M = 300 / 5
M = 60
In short, Your Answer would be 60
If You're looking for combined progress (average of class then, it would be: 50 + 60 /2 = 110/2 = 55
Hope this helps!