Problem 1
Draw a straight line and plot X anywhere on it.
Use your compass to trace out a circle with radius 1.5 cm. The circle intersects the line at two points. Let's make Y one of those points.
Also from point X, draw a circle of radius 2.5
This second circle will intersect another circle of radius 3.5 and this third circle is centered at point Z.
Check out the diagram below to see what I mean.
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Problem 2
Draw a straight line and plot L anywhere on it.
Adjust your compass to 4 cm in width. Draw a circle around point L.
This circle crosses the line at two spots. Focus on one of those spots and call it M.
Draw another circle centered at point M. Keep the radius at 4 cm.
The two circles intersect at two points. Focus on one of the points and call it N.
The last step is to connect L, M and N to form the equilateral triangle.
See the image below.
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Problem 3
I'm not sure how to do this using a compass and straightedge. I used GeoGebra to make the figure below instead. It's a free graphing and geometry program which is very useful. I used the same app to make the drawings for problem 1 and problem 2 earlier.
Answer:
3/18 or 1/9
Step-by-step explanation:
2/3 divided by 6 = ?
2 1 3
- x - = -
3 6 18
3/18
Answer:
The piecewise equation is given as :
Step-by-step explanation:
Let x be the time in hour and A(x) be the amount of accumulating rainfall at time x.
We are given that in the first three hours the rain fell at a constant rate of 25mm per hour
Amount of rainfall in 1 hour = 25
Amount of rainfall in t hours = 25x

The rain then slows down and remains constant
So, Amount of rain for that hour = 
75 mm ; 3
Now we are given that started again at a constant rate of 20 mm per hour for the next two hours.
Amount of rain after 4 hours = 
The rain increases at a rate of 20t from 4 ≤ x ≤ 6.
Hence the piecewise equation is given as :
Yes it would be one because anything with the 0 on the upper corner is 1