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GaryK [48]
3 years ago
14

A state university locks in costs for a student once a student starts attending the university. The total cost is $23,500. A stu

dent has
the following help in covering the costs of school.
• An academic scholarship of $8,200.
• Other scholarships and grants of $7.400.
Grandparents pay $1,000
.
What is the amount that the student will need to save every month in order to pay off the remaining costs in 10 months ?
$690
S820
S1 660
$2 350
Mathematics
1 answer:
Anestetic [448]3 years ago
7 0

Answer:

720

Step-by-step explanation:

24500 (total) subtracted by (10,700 + 5000 + 1600) =7200. 7200 divide by 10 mo=720

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-2x+y=9<br><br><br> I need to isolate y
anygoal [31]

Answer:

y =2x+9

Step-by-step explanation:

-2x+y=9

Add 2x to each side

-2x+2x+y=2x+9

y =2x+9

7 0
3 years ago
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Crash Hospital Costs. A study was conducts to estimate hospital costs for accident victims who wore seat belts. Twenty randomly
kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =9004 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=20-1=19

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that t_{\alpha/2}=2.86

Now we have everything in order to replace into formula (1):

9004-2.86\frac{5629}{\sqrt{20}}=5004.168    

9004+2.86\frac{5629}{\sqrt{20}}=12603.832

So on this case the 99% confidence interval would be given by (5004.168;12603.832)    

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

7 0
3 years ago
Frank is trying to factor y^2+6y-27 . He has determined that one factor is (y + 9). What is the other factor? A. y – 27 B. y – 6
beks73 [17]
The other factor is (y - 3).  If you multiply the two terms together, you will end up with y^2+6y-27:

(y - 3)(y + 9) \\ y^{2} +9y-3y-27 \\ y^2+6y-27
5 0
3 years ago
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Sybil has 1/2 of a pizza left over. She wants to share the pizza with 3 of her friends. What fraction of the original pizza will
Helen [10]

Answer: \frac{1}{2\times3}=\frac{1}{6}\text{ of the original pizza.}


Step-by-step explanation:

Given: Sybil has 1/2 of a pizza left over.

If she share the pizza with 3 of her friends, to find the fraction of the original pizza will Sybil and her 3 friends each receive, we need to divide 1/2 by 3 we get

The  fraction of the original pizza will Sybil and her 3 friends each receive

=\frac{\frac{1}{2}}{3}=\frac{1}{2\times3}=\frac{1}{6}\text{ of the original pizza.}



6 0
3 years ago
Read 2 more answers
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of
steposvetlana [31]

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

Step-by-step explanation:

  • From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack)  P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
  • A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen or an ace.

P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13

  • WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the  probability that they will both be aces?

P(AA) = (4/52)(3/51) = 1/221.

  • WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a  king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been  removed.

  • WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick  a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

  • The probability of drawing the second queen is also  4/52 and the third is 4/52.
  • We multiply these three individual probabilities together to get P(QQQ) =
  • P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
  • Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
5 0
3 years ago
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