Answer:
y = 4x - 19
Step-by-step explanation:
The line is parallel to the line whose equation is;
y = 4x + 1
Parallel lines have the same slope so the slope of our line is 4.
The line passes through point (5,1)
Slope = change in y ÷ change in x
Taking another point (x,y) on the line,
Slope = 
= 4
y - 1 = 4x - 20
y = 4x - 19
the yearly increase of x% assumes is compounding yearly, so let's use that.
![95000=80000\left(1+\frac{~~ \frac{r}{100}~~}{1}\right)^{1\cdot 5}\implies \cfrac{95000}{80000}=\left( 1+\cfrac{r}{100} \right)^5 \\\\\\ \cfrac{19}{16}=\left( 1+\cfrac{r}{100} \right)^5\implies \sqrt[5]{\cfrac{19}{16}}=1+\cfrac{r}{100}\implies \sqrt[5]{\cfrac{19}{16}}=\cfrac{100+r}{100} \\\\\\ 100\sqrt[5]{\cfrac{19}{16}}=100+r\implies 100\sqrt[5]{\cfrac{19}{16}}-100=r\implies 3.5\approx r](https://tex.z-dn.net/?f=95000%3D80000%5Cleft%281%2B%5Cfrac%7B~~%20%5Cfrac%7Br%7D%7B100%7D~~%7D%7B1%7D%5Cright%29%5E%7B1%5Ccdot%205%7D%5Cimplies%20%5Ccfrac%7B95000%7D%7B80000%7D%3D%5Cleft%28%201%2B%5Ccfrac%7Br%7D%7B100%7D%20%5Cright%29%5E5%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B19%7D%7B16%7D%3D%5Cleft%28%201%2B%5Ccfrac%7Br%7D%7B100%7D%20%5Cright%29%5E5%5Cimplies%20%5Csqrt%5B5%5D%7B%5Ccfrac%7B19%7D%7B16%7D%7D%3D1%2B%5Ccfrac%7Br%7D%7B100%7D%5Cimplies%20%5Csqrt%5B5%5D%7B%5Ccfrac%7B19%7D%7B16%7D%7D%3D%5Ccfrac%7B100%2Br%7D%7B100%7D%20%5C%5C%5C%5C%5C%5C%20100%5Csqrt%5B5%5D%7B%5Ccfrac%7B19%7D%7B16%7D%7D%3D100%2Br%5Cimplies%20100%5Csqrt%5B5%5D%7B%5Ccfrac%7B19%7D%7B16%7D%7D-100%3Dr%5Cimplies%203.5%5Capprox%20r)
Answer:
3 11/20
Step-by-step explanation:
Total gallons of water=7
Spring water=two and one-fourth gallon=2 1/4
Filtered water=one and one-fifth
=1 1/5
Spring water+filtered water=2 1/4 + 1 1/5
=9/4+6/5
= 45+24/20
=69/20
=3 9/20
How many gallons of water were not spring or filtered
=Total gallons- (spring+ filtered water)
=7-69/20
=140-69/20
=71/20
=3 11/20
Answer:
Step-by-step explanation:
First, start by converting 4 feet to inches. Note that 1 foot = 12 inches.
Set up a unit converter:
The ft cancel out leaving us with:
Now, we can set up a scale factor...
