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Lerok [7]
3 years ago
10

Please help me

Mathematics
2 answers:
Sedbober [7]3 years ago
4 0
The answer is 0.2
Hope this helps
krok68 [10]3 years ago
3 0

Answer:

0.2

Step-by-step explanation:

HP I HELPED :3

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Robin had twenty-five math problems and thirty-six science problems for homework. If she finished thirty-four of the problems at
Mashutka [201]

Answer:

27 problems are remaining to solve

3 0
3 years ago
Find the perimeter of the figure to the nearest hundredth. 20mm 20mm 16mm. Please help me!
Sidana [21]

Answer:

The perimeter is 56mm

Step-by-step explanation:

N/B: the figure is not given, nevertheless we can infer that the figure is a triangular figure given that the lengths provided is just three.

So the perimeter is the distance around the object.

Perimeter =20+20+16= 56mm

6 0
3 years ago
Surveys tend to suffer from low response rates. Based on past​ experience, a researcher determines that the typical response rat
devlian [24]

Answer:

B.

Step-by-step explanation:

First let's define the different bias that exist:

Sampling bias: This bias occurs when the method used to get the sample favours one part of the population leaving another part of the population excluded.

Non response bias: This bias occurs when the people who do not answer the survey have different opinions from the ones who do.

Response bias: This bias occurs when the answer given to the survey does not reflect the true feelings of the person who responds.

Now back to the problem:

  • The researcher sent the survey to 2000 randomly selected e-mail addresses, she expects to get 20% of responses, meaning 400 people will answer the survey.

Given these conditions, we would expect the survey to be biased. We have approximately 1600 people who didn't answer the survey so it is possible that all these people who didn't answer have different opinions from the 400 who did (non response bias), given that the survey was done by email it could also happen that people do not tell the truth when asked about a topic (response bias), also, there would be sampling bias because the people who she selected have an email address so the people who don't use email get excluded from the survey (sampling bias)

6 0
3 years ago
Find the approximate side length of a square game board with an area of 171 in?
Makovka662 [10]

<em>Greetings from Brasil...</em>

According to the statement of the question, we conclude that the area of a square is requested, whose value is 171 in²

The area of a square is given by the expression:

A = S²

<em>where S is the side of the square - just what we want to know</em>

So:

A = S²

171 = S²

√171 = S

<h3>S ≈ 13.08in</h3>
8 0
4 years ago
A clinical psychologist wants to test whether experiencing childhood trauma reduces one's self-efficacy in adulthood. He randoml
lidiya [134]

Answer:

No, there is not any sufficient evidence to conclude that individuals who have experienced childhood trauma have lower self-efficacy in adulthood.

Step-by-step explanation:

We are given that a clinical psychologist wants to test whether experiencing childhood trauma reduces one's self-efficacy in adulthood.

He randomly selects 22 adults who have experienced childhood trauma and finds that their mean self-efficacy score equals 118.1.

Self-efficacy scores in the general population of adults are distributed normally with a mean equal to 118.5 and a standard deviation equal to 18.8 .

<em>Let </em>\mu<em> = mean self-efficacy score.</em>

So, Null Hypothesis, H_0 : \mu \geq 118.5      {means that the individuals who have experienced childhood trauma have higher or same self-efficacy in adulthood}

Alternate Hypothesis, H_A : \mu < 118.5    {means that the individuals who have experienced childhood trauma have lower self-efficacy in adulthood}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                      T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean self-efficacy score = 118.1

            \sigma = population standard deviation = 18.8

          n = sample of adults who have experienced childhood trauma = 22

So, <u><em>test statistics</em></u>  =  \frac{118.1-118.5}{\frac{18.8}{\sqrt{22} } }  

                              =  -0.0998

The value of z test statistics is -0.0998.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the z table gives critical value of -1.645 for left-tailed test.</u>

Since our test statistic is more than the critical value of z as -0.0998 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the individuals who have experienced childhood trauma have higher or same self-efficacy in adulthood.

4 0
4 years ago
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