Answer:
a = 2
Step-by-step explanation:
We can use cross products to solve
8 a
----- = -------
28 7
8*7 = 28*a
Divide each side by 28
56/28 = 28a/28
2 =a
Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
Answer:
In ∆ABD and ∆ACD
<BAD =<CAD ( each are half of <A )
<D=<D ( each equal to 90°)
AD = AD ( common)
So ∆ ABD is congruent to ∆ ACD.
Then AB =AC (by C.P.C.T)
Hence,∆ABC is an iso - sceles triangle.
The point of observation is 2500 m away from the foot of the building.
The angle of elevation is 4°.
We need to find the height 'h' of the building.
With respect to 4°,
2500 is the adjacent side.
'h' is the opposite side.
The trigonometric ratio associating opposite & adjacent is tan.
We have
Cross multiplying we get
h = 2500 tan4°
h= 174.82 m
Option B) is the right answer.
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I'm not for sure if this is what you meant though sorry
