How to solve x+6y=1 and 2x-3y=32

1 answer:

3 0

$\left\{\begin{array}{ccc}x+6y=1\\2x-3y=32&\text{multiply both sidess by 2}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}x+6y=1\\4x-6y=64\end{array}\right}\\.\qquad5x=65\qquad\text{dicide both sides by 5}\\.\qquad\boxed{x=13}\\\\\text{Put the value of x to the first equation}\\\\13+6y=1\qquad\text{subtract 13 from both sides}\\\\6y=-12\qquad\text{divide both sides by 6}\\\\\boxed{y=-2}\\\\Answer:\ \boxed{x=13\ and\ y=-2\to(13,\ -2)}$

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