Answer:
The domain is all values but x=4 and x=2
Step-by-step explanation:
f(x) = (x+1) / ( x^2-6x+8)
Factor the function
f(x) = (x+1) / ( (x-4) ( x-2))
The domain of the function is all values of x except where the function does not exist
This is where the denominator goes to zero
(x-4) ( x-2) =0
Using the zero product property
x-4 =0 x-2 =0
x=4 x=2
The domain is all values but x=4 and x=2
Answer:
D
Step-by-step explanation:
There is only one variable in this situation which means you can rule out A and C, B is wrong because it said it wants Y, so D is your answer!
Remark
What this is telling you to do is put 3x + 3 in the question wherever there was an x to start with.
Solution
f(x) = -3x + 4
f(3x + 3) = - 3(3x + 3) + 4
f(3x + 3) = -3*3x + (-3)*(3) + 4
f(3x + 3) = - 9x - 9 + 4
f(3x + 3) = -9x - 5 <<<<< Answer
Answer:
Part 1:
Yes, the side lengths form a right triangle.
Part 2:
Option d 37.1 cm
Explanation:
We need to use the pythagorean theorem.
In part 1, if the 3 side lengths are a right triangle, then, they must verify:
By the theorem. Then:
They're equal, then the lengths correspond to a right triangle.
For part 2, we need to use again the theorem. In this case:
Pascals triangle to the 6th:
1 x^0
1 1 x^1
1 2 1 x^2
1 3 3 1 x^3
1 4 6 4 1 x^4
1 5 10 10 5 1 x^5
1 6 15 20 15 6 1 x^6<span>
</span>the problem is to the 6th power so your going to use the 6th row of pascals triangle (don't count the first row). these numbers represent the coefficients of the variables
1(d-5y)^6 + 6(d-5y)^5 + 15(d-5y)^4 + 20(d-5y)^3 + 15(d-5y)^2 + 6(d-5y) + 1
then simplify
