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PIT_PIT [208]
3 years ago
9

What is the area of this parallelogram? ____sq ft

Mathematics
2 answers:
shutvik [7]3 years ago
5 0

Answer:

A=8.6

Step-by-step explanation:

b Base  4.3

h Height     2.0

Thus: 2*4.3 = 8.6

Pachacha [2.7K]3 years ago
4 0

Answer:8.6


Step-by-step explanation:

Multiply base times height which is b*h

Base is 4.3

And height is 2

Multiply them by plunging in answers for example b=4.3 *height 2 =

Equals 8.6


Please mark me brainliest


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What is the first step in the construction of a line perpendicular to and passing through an external point M? Assume that the c
AVprozaik [17]

Answer:

A.)lPace the compass needle on M and, keeping the compass width the same, draw two arcs that intersect

Step-by-step explanation:

In the construction of a line perpendicular to AB←→ and passing through an external point M the first step must be"Place the compass needle on M and, keeping the compass width the same, draw two arcs that intersect AB←→". After that you can draw arcs from intersection points (keeping the compass width same as before) to the opposite side of M, name it as N than use straightedge to draw line passes through M and n that would be perpendicular line to AB.

4 0
3 years ago
F(x) = -22 – 4x<br> Find f(-1)
LUCKY_DIMON [66]
= -22-4(-1)
= -22+4
= -18
3 0
3 years ago
Read 2 more answers
find a positive angle less than one revolution around the unit circle that is co-terminal with the given angle -15pi/17
natta225 [31]
ANSWER
=\frac{19}{17} \pi

EXPLANATION

To find a positive angle that is coterminal with
-  \frac{15}{17}  \pi

We add multiples of 2π until we get a positive angle that is less than one revolution,


We add to obtain,


-  \frac{15}{17}  \pi + 2\pi


This simplifies to,

=  \frac{19}{17} \pi

This is the first positive angle that is coterminal with
-  \frac{15}{17}  \pi


and is less than one revolution.
7 0
3 years ago
Help anyone can help me do the question 4,I will mark brainlest.​
nasty-shy [4]

Answer:

Hello,

Step-by-step explanation:

A=(1,2)\\B=(0,-1)\\\overrightarrow{AB}=((0,-1)-(1,2)=(-1,-3)\ ||\overrightarrow{AB}||^2=1+9=10\\\overrightarrow{BC}=((3,-2)-(0,-1)=(3,-1)\ ||\overrightarrow{BC}||^2=9+1=10\\\\Triangle\ is\ isosceles.\\\\\overrightarrow{AB}.\overrightarrow{BC}=(-1,-3)*\left[\begin{array}{c}3\\-1\end{array}\right] =-3+3=0\\\\Triangle \ is\ right.\\\\

8 0
3 years ago
Read 2 more answers
How many arrangements can be made using 2 letters of the word HYPERBOLAS if no letter is to be used more than once?
alisha [4.7K]

Answer:

90 arrangements

Step-by-step explanation:

Since there are no repititions of letters, there are unique  10 letters in total.

THe number of arrangements would be 2 permutation 10. We need the formula for permutation. That is:

nPr=\frac{n!}{(n-r)!}\\

Now, n = 10 [total] and r is 2, so we have:

nPr=\frac{n!}{(n-r)!}\\\\_{10}P_{2}=\frac{10!}{(10-2)!}\\=\frac{10!}{8!}\\=\frac{10*9*8!}{8!}\\=10*9\\=90

So, there can be 90 arrangements

3 0
3 years ago
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