Given:
The sum of two terms of GP is 6 and that of first four terms is 
To find:
The sum of first six terms.
Solution:
We have,
Sum of first n terms of a GP is
...(i)
Putting n=2, we get
...(ii)
Putting n=4, we get
(Using (ii))
Divide both sides by 6.
Taking square root on both sides, we get
Case 1: If r is positive, then using (ii) we get
The sum of first 6 terms is
Case 2: If r is negative, then using (ii) we get
The sum of first 6 terms is
Therefore, the sum of the first six terms is 7.875.
A circumscribed angle is that which is formed by the intersection of the two tangent lines in a circle. With this, we can conclude that segments AC and AB are tangent to circle O. The tangent lines forms a right angle with the radius of the circle drawn from the center of the circle to the tangent point.
By the explanation above, we can say that angles C and B are equal to 90° and that triangle ACO and triangle ABO are congruent. Which means that segment AC is equal to segment AB. Thus, the length of AB is also 4.
<em>Answer: 4 units</em>
(-2x+4)+2(2x+1)= -2(-x-3)
Convert to a mixed number:
239/42
Divide 239 by 42:
4 | 2 | 2 | 3 | 9
42 goes into 239 at most 5 times:
| | | | 5
4 | 2 | 2 | 3 | 9
| - | 2 | 1 | 0
| | | 2 | 9
Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:
| | | | 5 | (quotient)
4 | 2 | 2 | 3 | 9 |
| - | 2 | 1 | 0 |
| | | 2 | 9 | (remainder)
The quotient of 239/42 is 5 with remainder 29, so:
Answer: 5 29/42
Answer:
60%
Step-by-step explanation:
40 / 25 - 1 = 60%
