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Katarina [22]
3 years ago
6

Which of the following BEST describes a body in equilibrium?

Health
2 answers:
erma4kov [3.2K]3 years ago
5 0

Answer:

B All forces acting on a body are balanced.

Explanation:

A body is in equilibrium when the sum of all forces acting on it is zero, ie zero, that is, all forces acting on that body are balanced. According to Newton's First Law, when the resultant forces acting on a body are null, the body remains in its resting state or in uniform rectilinear motion. Therefore, an object in equilibrium may be at rest or in uniform rectilinear motion.

sukhopar [10]3 years ago
4 0

\textsf {\large{\underline { \underline {SOLUTION:-}}}}

⇰Let O be the point of observation on the ground OX.

⇰Let A and B be the two positions of the jet.

\bf➠Then, \angle XOA=60⁰ \: and   \: \angle \: XOB=30⁰ \\  \\

\bf ➠Draw \:   AL \perp \: OX \: and  \: BM \perp \: OX \\  \\

\bf \:⇰ Let \: AL=BM=h \: meters. \\  \\

\bf \: ⇰ \: Speed \: of \: Jet  = 720 \: km/hr\\

\bf =  \huge( \small \: 720 \times  \frac{5}{18}  \huge) \small \: m / s\\

\bf = 200 \: m/s

\bf \:➥ Time  \: taken \: to \: cover \: the \: distance  \: AB=15  \: sec  \\  \\

\bf➥ Distance  \: covered =(speed×time) \\  \\

\:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \bf = (200 \times 15)m = 3000m \\  \\

\bf \therefore LM=AB=3000m \\  \\

{ \bf \: ⇰  \: Let \: OL} = x   \:  \bf m \\  \\

\bf➥From  \: right  \: \triangle OLA, \: we \: have: \\

\bf \frac{OL}{AL} =cot \: 60⁰= \frac{1}{ \sqrt{3} } \implies \frac{x}{h}  =  \frac{1}{ \sqrt{3} }  \\  \\

\bf \implies \: x =  \frac{h}{ \sqrt{3} }  \:  \:  \:  \:  \:  \:  \: ....(1) \\  \\

\bf \:➥ From  \: right  \: \triangle \: OMB,we \: have: \\

\bf\frac{OM}{BM} =cot30⁰= \sqrt{3}  \\  \\

\bf \implies \:  \frac{x + 3000}{h}  =  \sqrt{3}  \\  \\

\bf[ \boxed{➯OM=OL+LM=OL+AB=(x+3000)m  \: and \: BM=h \: m]}

\bf \implies \: x + 3000 =  \sqrt{3} h \\

\bf \implies \: x = ( \sqrt{3} h - 3000) \:  \:  \:  \:  \:  \: ....(2) \\

⇰ Equating the value of x from (1) and (2),we get;

\bf \:  \sqrt{3} h - 3000  =  \frac{h}{ \sqrt{3} }  \\  \\

\implies \bf \: 3h  - 3000 \sqrt{3}  = h \\

\bf \implies \: 2h = (3000 \times  \sqrt{3} ) = (3000 \times 1.762) \\

\bf \implies \: h = (3000 \times 0.866) = 2598  \\  \\

\bf \:➥ Hence \: ,the \: required  \: height \: is \: \boxed{ \boxed{ \bf2598 \: m.}} \\  \\

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