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Mashcka [7]
3 years ago
10

If Mark is developing a website to be optimized for mobile devices, what would be the top-level domain?

Computers and Technology
1 answer:
umka2103 [35]3 years ago
5 0

Answer:

A top-level domain or the TLD is the domain at the highest level in the hierarchy of the DNS. And that means in the Internet DNS. Also, the top-level domain is installed in the namespace toot zone. And the top-level domain is the .com, in general, to be named as the best one. The next two are the .net and .org. But since it is required to optimize the website for the mobile devices, we should select here .com.

Explanation:

Please check the answer section.

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What were the important developments that occurred in photography that facilitated the creation of motion pictures? Two critical
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Answer:

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Explanation:

7 0
3 years ago
Write a program get_price.py with a function get_price() that takes a dictionary of fruits as an argument and returns the name o
yawa3891 [41]

Answer:

The program is as follows:

def get_price(fruits):

   AllPrice = fruits.values()

   value_iterator = iter(AllPrice)

   mostExpensive = next(value_iterator)  

   for item in fruits:

       if fruits[item]>=mostExpensive:

           mostExpensive = fruits[item]

           fruitName = item

   print(fruitName)

fruits = {}

n = int(input("Number of Fruits: "))

for i in range(n):

   name = input("Fruit name: ")

   price = int(input("Fruit price: "))

   fruits[name] = price

get_price(fruits)

Explanation:

This defines the get_price function

def get_price(fruits):

This gets all price in the dictionary fruit

   AllPrice = fruits.values()

This passes the values to a value iterator

   value_iterator = iter(AllPrice)

This initializes mostExpensive to the first price in the dictionary

   mostExpensive = next(value_iterator)

This iterates through the elements of the dictionary  

   for item in fruits:

If current element is greater than or equals most expensive

       if fruits[item]>=mostExpensive:

Set most expensive to the current element

           mostExpensive = fruits[item]

Get the corresponding fruit name

           fruitName = item

Print fruit name

   print(fruitName)

The main begins here

This initializes the fruit dictionary

fruits = {}

This gets input for the number of fruits

n = int(input("Number of Fruits: "))

This is repeated for every inputs

for i in range(n):

Get fruit name

   name = input("Fruit name: ")

Get fruit price

   price = int(input("Fruit price: "))

Append name and price to dictionary

   fruits[name] = price

Call the get_price function

get_price(fruits)

4 0
3 years ago
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