Answer:
b
Step-by-step explanation:
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
Answer:
0.31
Step-by-step explanation:
(2/7)-(3/8)+(2/5)
Answer: C) mC > mA > mB is correct regarding the angles of the triangle ABC.
Step-by-step explanation:
Given: In Δ ABC, the side lengths of triangle ABC are written in terms of the variable p, where p ≥ 3.
AB=4p-1 , AC=p+4 , BC=3p
where p+4 < 3p [as p≥3]
3p < 4p-1 [as p≥3]
⇒ 4p-1> 3p > p+4
⇒AB>BC>AC
Angle opposite to AB ,BC and AC is m∠C ,m∠A and m∠B.
Therefore mC > mB > mA [∵Angle opposite to greater side is greater]
Thus , mC > mA > mB is correct regarding the angles of the triangle ABC.
Given:
The length of the rectangle = 16 ft
The width of the rectangle = 12 ft
The diameter of the semicircle = 12 ft
To find the area of the given figure.
Formula
where,
be the area of the given figure
be the area of the rectangle
be the area of the semicircle.
- The area of the rectangle =
where, l be the length and b be the width - Area of the semicircle =
, r be the radius of the semicircle.
Now,
The radius of the semicircle r = 6 ft
Putting, r=6, l=16 and b= 12 we get,
sq ft
or, 
sq ft
sq ft
or, 
sq ft
So,
sq ft
= 248.52 sq ft
Rounding off to the nearest tenth, we get;
A=248.5 sq ft.
Hence,
The area of the composite figure is 248.5 sq ft.
It is equivalent to 16 cm
