Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as
Since the arithmetic mean is the sum of the values, divided by how many they are, we have
So, the mean of 11 consecutive integers is the 6th integer.
Answer: y = -3(x + )² +
,
,
<u>Step-by-step explanation:</u>
First, you need to complete the square:
y = -3x² - 5x + 1
<u> -1 </u> <u> -1 </u>
y - 1 = -3x² - 5x
y - 1 = -3(x² +
y - 1 + -3() = -3(x² +
+
)
↑ ↓ ↑
=
y - 1 - = -3(x +
)²
y - -
= -3(x +
)²
y - = -3(x +
)²
y = -3(x + )² +
Now, it is in the form of y = a(x - h)² + k <em>where (h, k) is the vertex</em>
Vertex = ,