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anzhelika [568]
3 years ago
11

A retail outlet for calculators sells 900 calculators per year. It costs ​$2 to store one calculator for a year. To​ reorder, th

ere is a fixed cost of ​$4​, plus ​$1.25 for each calculator. How many times per year should the store order​ calculators, and in what lot​ size, in order to minimize inventory​ costs?
Mathematics
1 answer:
Rus_ich [418]3 years ago
5 0

Answer:

In order to minimize cost the outlet must order 60 units 15 times a year.

Explanation:

Theoretically, the EOQ is the optimal order quantity that a firm should purchase in order to minimize its inventory costs (holding costs are included here), and costs of placing an order.

Mathematically:

EOQ= \sqrt{2SD} /H

Where:

D= demand

S= cost of placing an order.

H= holding cost (per unit and per year).

In the statement, we identify each of these values:

D= 900

S= 4

H= $2

EOQ= \sqrt{2SD} /H=√2*4*900/2= 60

Times per year= 900/60= 15

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Two sets of equatic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2: x
kherson [118]

Answer:  The correct line is

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Step-by-step explanation:  We are given the following two sets of quadratic expressions in various forms:

\textup{Line 1: }x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25,\\\\\textup{Line 2 :}x^2+5x+6=(x+2)(x+3)=(x+2.5)^2+6.25.

We are to select one of the lines from above that represent three equivalent expressions.

We can see that there are three different forms of a quadratic expression in each of the lines:

First one is the simplified form, second is the factorised form and third one is the vertex form.

So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.

We have

\textup{Line 1: }\\\\x^2+3x+2\\\\=x^2+2x+x+2\\\\=x(x+2)+1(x+2)\\\\=(x+1)(x+2),

and

x^2+3x+2\\\\=x^2+2\times x\times 1.5+(1.5)^2-(1.5)^2+2\\\\=(x+1.5)^2-2.25+2\\\\=(x+1.5)^2-0.25.

So,

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Thus, Line 1 contains three equivalent expressions.

Now,

\textup{Line 2: }\\\\x^2+5x+6\\\\=x^2+3x+2x+6\\\\=x(x+3)+2(x+3)\\\\=(x+2)(x+3),

and

x^2+5x+6\\\\=x^2+2\times x\times 2.5+(2.5)^2-(2.5)^2+6\\\\=(x+2.5)^2-6.25+6\\\\=(x+2.5)^2-0.25\neq (x+2.5)^2+6.25.

So,

\textup{Line 2 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2+6.25.

Thus, Line 2 does not contain three equivalent expressions.

Hence, Line 1 is correct.

7 0
3 years ago
Sakima Lena is employed at a restaurant. He has family medical coverage through the company’s group medical plan. The annual cos
omeli [17]

Answer: $2405

Step-by-step explanation: explanation is in the attached picture file

3 0
3 years ago
At noon joyce drove to the lake at 30 mph, but she made the long walk back home at 4 mph. how many hours did she walk if she was
lina2011 [118]
By definition we have the following equation:
 t = d / v
 Where,
 t: time
 d: distance
 v: speed
 For this case we have:
 d / 30 + d / 4 = 17
 Rewriting we have:
 2d + 15d = 17 (60)
 17d = 17 (60)
 d = 60 mi
 Then, the walking time is
 t = d / v
 t = 60/4
 t = 15 hours
 Answer:
 
She walked
 
t = 15 hours
4 0
3 years ago
Can anyone help me please
kicyunya [14]

Answer:

yes wait im doing it. do I put them un order

3 0
3 years ago
Assume that the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. If th
ioda

Answer:

The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mean of 69.0 inches and a standard deviation of 2.8 inches.

This means that \mu = 69, \sigma = 2.8

What is the bottom cutoff heights to be eligible for this experiment?

The bottom 15% are excluded, so the bottom cutoff is the 15th percentile, which is X when Z has a pvalue of 0.15. So X when Z = -1.037.

Z = \frac{X - \mu}{\sigma}

-1.037 = \frac{X - 69}{2.8}

X - 69 = -1.037*2.8

X = 66.1

The bottom cutoff heights to be eligible for this experiment is 66.1 inches.

8 0
3 years ago
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