Answer:
r= 2 √(15/π)
Step-by-step explanation:
Given that :
Area of circle =60sq cm
radius=√60/π
![Area=\pi r^2\\60=\pi r^2\\\\\sqrt{\frac{60}{\pi}}=r\\\\\sqrt{\frac{15\times 4}{\pi}}=r\\2\sqrt{\frac{15}{\pi}}=r](https://tex.z-dn.net/?f=Area%3D%5Cpi%20r%5E2%5C%5C60%3D%5Cpi%20r%5E2%5C%5C%5C%5C%5Csqrt%7B%5Cfrac%7B60%7D%7B%5Cpi%7D%7D%3Dr%5C%5C%5C%5C%5Csqrt%7B%5Cfrac%7B15%5Ctimes%204%7D%7B%5Cpi%7D%7D%3Dr%5C%5C2%5Csqrt%7B%5Cfrac%7B15%7D%7B%5Cpi%7D%7D%3Dr)
Hence the radius can be written as 2 √(15/π)
Answer:
The missing factor is (9s+1)
Step-by-step explanation:
The missing factor is (9s+1) because of the following
(9s^2 + s) + (18s+2)
If we factor out s from 9s^2+s, we get s(9s+1).
If we factor out 2 from 18s+2, we get 2(9s+1)
putting these together, we get s(9s+1) + 2(9s+1). Factoring out the common term of 9s+1, we get (9s+1)(s+2). therefore, the missing factor is 9s+1
Answer:
sound like a personal problem
Step-by-step explanation:
cuz
The sum is 12x3+18x2-10x+8
Answer:
A. (−3,5)
Step-by-step explanation:
The rule for dilation by scale factor k is given by:
![(x,y)\to (kx,ky)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%20%28kx%2Cky%29)
The given point is P(-3,5) and the scale factor is k=1
We substitute the point and the scale factor into the rule to get:
![P(-3,5)\to P'(-3\times1,5\times1)](https://tex.z-dn.net/?f=P%28-3%2C5%29%5Cto%20P%27%28-3%5Ctimes1%2C5%5Ctimes1%29)
This gives us:
![P(-3,5)\to P'(-3,5)](https://tex.z-dn.net/?f=P%28-3%2C5%29%5Cto%20P%27%28-3%2C5%29)
The correct answer is A