What is a suitable way to display relationship between two continuous variables?
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Hello oddworld7836!
Factor the expression into an equivalent form 12y² - 75.
By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.
Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,
- a² = 4, a = 2 (√a² = ✓4 = 2)
- b² = 25, b = 5 (√b² = ✓25 = 5)
So, the (4y² + 25) becomes...
Now, bring the 3 (common factor) & rewrite the complete expression.
We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.
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Hope it'll help you!
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