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bogdanovich [222]
4 years ago
13

How to solve 3/4x=6.

Mathematics
1 answer:
Anit [1.1K]4 years ago
6 0

Answer:

9/2 or 4.5

Step-by-step explanation:

3/4x=6

4x=6x3

x=18/4

x=9/2 or 4.5

You might be interested in
A study tested whether significant social activities outside the house in young children affected their probability of later dev
Alona [7]

Answer:

Step-by-step explanation:

From the question we are told that

   The first  sample size is  n_1   =  1000

    The second sample size is n_2 =  6000

    The number that had significant outside activity in the sample with ALL is  k_1 =  700

    The number that had significant outside activity in the sample without  ALL is  k_2 =  5000

Considering question a

   The percentage of children with ALL have significant social activity outside the home when younger is mathematically represented as

               \^ p_1   =  \frac{700}{1000}  * 100

=>            \^ p_ 1 = 0.7 =  70\%

Considering question b

   The percentage of children without  ALL have significant social activity outside the home when younger is mathematically represented as

               \^ p_2   =  \frac{5000}{6000}

=>            \^ p_ 2 =  0.83

Generally the sample odds ratio for significant social activity outside the home when younger, comparing the groups with and without ALL is mathematically represented as

           r =  \frac{\* p _1}{ \^  p_2 }

=>      r =  \frac{0.7}{ 0.83 }

=>      r = 0.141    

Considering question  c

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the lower limit of the  95% confidence interval for the population odds ratio for significant social activity outside the home when younger, comparing the groups with and without ALL is mathematically represented as

      a =  e^{ln  ( r ) -  Z_{\frac{\alpha }{2}} \sqrt{ [ \frac{1}{ k_1 } ] + [ \frac{1}{ c_1 } ] + [\frac{1}{k_2} ] + [\frac{1}{ c_2 } ]  } }

Here c_1 \  and  \ c_2 are the non-significant values i.e people that did not play outside when they were young in both samples

The values are

     c_1 =  1000 - 700 =  300

and  c_2 =  6000 - 5000

=>     c_2 = 1000

=>   a =  e^{ln  ( 0.141 ) -  1.96  \sqrt{ [ \frac{1}{ 700 } ] + [ \frac{1}{ 1000} ] + [\frac{1}{5000} ] + [\frac{1}{ 300 } ]  } }

=>   a =  0.1212

Generally the upper limit of the  95% confidence interval for the population odds ratio for significant social activity outside the home when younger, comparing the groups with and without ALL is mathematically represented as

    b =  e^{ln  ( 0.141 ) +  1.96  \sqrt{ [ \frac{1}{ 700 } ] + [ \frac{1}{ 1000} ] + [\frac{1}{5000} ] + [\frac{1}{ 300 } ]  } }

    b  =  0.1640

Generally  the 95% confidence interval for the population odds ratio for significant social activity outside the home when younger, comparing the groups with and without ALL is  

        95\% CI  =  [ 0.1212 , 0.1640  ]

Generally looking and the confidence interval obtained we see that it is less that 1  hence this means that there is a greater odd of developing ALL  in  groups with insignificant social activity compared to groups with significant social activity

3 0
3 years ago
The boundary lines for the system of inequalities is given in the graph.
diamong [38]

Answer:

C)

region C

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

\displaystyle y ≤ -x + 2

0 ≤ 2 ☑ [We shade the portion of the graph that CONTAIN THE ORIGIN, which is the bottom portion.]

\displaystyle y ≥ 2x - 3

0 ≥ −3 ☑ [We shade the portion of the graph that CONTAINS THE ORIGIN, which is the left side.]

So, now that we got that all cleared up, we can tell that both graphs share a region where the ORIGIN IS VISIBLE. Therefore region C matches the above inequalities.

I am joyous to assist you anytime.

4 0
4 years ago
Read 2 more answers
Suppose the equation E = $500 + $7x represents a person's earnings (+) for
Sholpan [36]

Answer:

Option D : $780 is the correct answer.

Step-by-step explanation:

Given expression is:

E = $500 + $7x

We will put all the values of given options to check.

A. Putting 430 in given expression

430 = 500 + 7x

430 - 500 = 7x

-70 = 7x

As the number of items sold cannot be negative, therefore, this option is not correct.

B. 530 = 500 + 7x

530 - 500 = 7x

30 = 7x

x = 4.3 (By dividing both sides by 7)

Which is not a whole number.

C. 680 = 500 + 7x

680 - 500 = 7x

7x = 180

x = 25.71

Which is also not a whole number.

D. 780 = 500 + 7x

780 - 500 = 7x

280 = 7x

7x = 280

x = 40

Which is a whole number.

Hence,

Option D : $780 is the correct answer.

4 0
3 years ago
Which value of x would make this equation true? 4x-10=18
garik1379 [7]
1) move the 10 over to the other side which would give you 28.
2) divide by 4 to get x by itself.

ANSWER: 7
4 0
3 years ago
Read 2 more answers
Leasing a car for a five-year period usually costs about the same as a five-year loan because __________.
NISA [10]
Here is the correct answer that would best complete the given statement above. Leasing a car for a five-year period usually costs about the same as a five-year loan because <span>even with the lower monthly payments, leasing a car for five years requires a second lease agreement, which comes with additional fees. Therefore, the correct answer would be option D. Hope this helps.</span>
7 0
3 years ago
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