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3 years ago

The boundary lines for the system of inequalities is given in the graph.

Mathematics

2 answers:

diamong [38]3 years ago

4 0

Answer:

region C

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

$\displaystyle y ≤ -x + 2$

0 ≤ 2 ☑ [We shade the portion of the graph that CONTAIN THE ORIGIN, which is the bottom portion.]

$\displaystyle y ≥ 2x - 3$

0 ≥ −3 ☑ [We shade the portion of the graph that CONTAINS THE ORIGIN, which is the left side.]

So, now that we got that all cleared up, we can tell that both graphs share a region where the ORIGIN IS VISIBLE. Therefore region C matches the above inequalities.

I am joyous to assist you anytime.

Goshia [24]3 years ago

4 0

Answer:

Step-by-step explanation:

on edg 2020 :)

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Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl

Karo-lina-s [1.5K]

Full Question

Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordless, and the other six are corded phones. Suppose that these components are randomly allocated the numbers 1, 2, . . . , 18 to establish the order in which they will be serviced.

What is the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced?

What is the probability that two phones of each type are among the first six serviced?

Answer:

a. 0.149

b. 0.182

Step-by-step explanation:

Given

Number of telephone= 18

Number of cellular= 6

Number of cordless = 6

Number of corded = 6

There are 18C6 ways of choosing 6 phones

18C6 = 18564

From the Question, there are 3 types of telephone (cordless, Corded and cellular)

There are 3C2 ways of choosing 2 out of 3 types of television

3C2 = 3

There are 12C6 ways of choosing last 6 phones from just 2 types (2 types = 6 + 6 = 12)

12C6 = 924

There are 2 * 6C6 * 6C0 ways of choosing none from any of these two types of phones

2 * 6C6 * 6C0 = 2 * 1 * 1 = 2.

So, the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced is

3 * (924 - 2) / 18564

= 3 * 922/18564

= 2766/18564

= 0.149

There are 6C2 * 6C2 * 6C2 ways of choosing 2 cellular, 2 cordless, 2 corded phones

= (6C2)³

= 3375

So, the probability that two phones of each type are among the first six serviced is

= 3375/18564

= 0.182

5 0

3 years ago

What is the value of y if f||n ?????

Elenna [48]

Answer:

y = 148°

Step-by-step explanation:

4x - 18 = 2x + 12 (alternate exterior angles are congruent)

Collect like terms

4x - 18 = 2x + 12

4x - 2x = 18 + 12

2x = 20

Divide both sides by 2

x = 10

y = 180 - (2x + 12) (linear pair theorem)

Plug in the value of x

y = 180 - (2(10) + 12)

y = 180 - (20 + 12)

y = 148°

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3 years ago

Rewrite 7.25 as a mixed number in lowest terms. 7 25/100 7 2/5 7 1/5 7 1/4

Galina-37 [17]

7.25 = 7 and 25/100 = 7 and 1/4

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4 years ago

Read 2 more answers

What is the value of a?

emmasim [6.3K]

Answer:

A=8

Step-by-step explanation:

If you use the formula 30-60-90 which is a-radical 3a-2a

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3 years ago

Need help ASAP Please

Eduardwww [97]

Answer:

area: $16x^2+24x+9$ Perimeter: 16x+12

Step-by-step explanation:

area : $(4x+3)^2$

thats $16x^2+24x+9$

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Red

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4 years ago

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