Question

Work out the size of the angle

Answer 1

Answer:<CDA≈ 47.5 degrees

Step-by-step explanation:

I note M , so BM _|_ AD

in trg ABM, T Pitagora

AM^2=AB^2-BM^2

AM^2=6.5^2-6^2

AM^2=42.25-36

AM^2=6.25

AM=2.5

I note N , so CN_|_  AD

AD=AM+MN+ND

23=2.5+9+ND

23=11.5+ND

ND=23-11.5

ND=11.5

in trg CND

tg <CDA=CN/ND

=6/11.5

=1.(09)

so <CDA≈ 47.5 degrees