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Tems11 [23]
3 years ago
9

Work out the size of the angle

Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:<CDA≈ 47.5 degrees

Step-by-step explanation:

I note M , so BM _|_ AD

in trg ABM, T Pitagora

AM^2=AB^2-BM^2

AM^2=6.5^2-6^2

AM^2=42.25-36

AM^2=6.25

AM=2.5

I note N , so CN_|_  AD

AD=AM+MN+ND

23=2.5+9+ND

23=11.5+ND

ND=23-11.5

ND=11.5

in trg CND

tg <CDA=CN/ND

=6/11.5

=1.(09)

so <CDA≈ 47.5 degrees

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What is the percentage of 48g of fat out of a 70g allowance
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The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and
Delicious77 [7]

The width of rectangle is 2\frac{1}{4}\ cm and length is 5\frac{5}{12}\ cm

Step-by-step explanation:

Let,

Width of rectangle = w

Length of rectangle = w+3\frac{1}{6}=w+\frac{19}{6}

Perimeter of rectangle = 15\frac{1}{3}=\frac{46}{3}\ cm

Perimeter of rectangle = 2(Length + Width)

2(w+\frac{19}{6}+w)=\frac{46}{3}\\2(2w+\frac{19}{6})=\frac{46}{3}\\4w+\frac{19}{3}=\frac{46}{3}

Subtracting \frac{19}{3} from both sides

4w+\frac{19}{3}-\frac{19}{3}=\frac{46}{3}-\frac{19}{3}\\4w=\frac{46-19}{3}\\4w=\frac{27}{3}\\4w=9

Dividing both sides by 4

\frac{4w}{4}=\frac{9}{4}\\w=\frac{9}{4}

Therefore,

Width of rectangle = w = \frac{9}{4}=2\frac{1}{4} cm

Length of rectangle = w+\frac{19}{6}=\frac{9}{4}+\frac{19}{6}=\frac{27+38}{12}=\frac{65}{12}=5\frac{5}{12}\ cm

The width of rectangle is 2\frac{1}{4}\ cm and length is 5\frac{5}{12}\ cm

Keywords: perimeter, addition

Learn more about addition at:

  • brainly.com/question/6270221
  • brainly.com/question/6275033

#LearnwithBrainly

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3 years ago
Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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3 years ago
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Answer:

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Step-by-step explanation:

do it on a calculator (TI84)

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