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2 years ago

Pls help me with my math

Mathematics

1 answer:

navik [9.2K]2 years ago

8 0

The statement is TRUE, because the number 0 is a solution to the inequality.

<h3>What is a Solution to an Inequality Statement?</h3>

A solution to a given inequality statement is the value of the variable that makes the statement true when plugged into the inequality.

Given the inequality statement, -4 < w + 4 ≤ 6, substitute x = 0 into the inequality to determine if it is a solution to the inequality:

-4 < 0 + 4 ≤ 6

-4 < 4 ≤ 6 [this implies that -4 is less than 4, and 4 is less than or equal to 6]

4 is less than 6, and -4 is also less than 4. This means the inequality statement is correct or true.

Therefore, we can state that, the number 0 is a solution to the inequality.

Learn more about solution to an inequality on:

brainly.com/question/11613554

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A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

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Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

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Answer:

Step-by-step explanation:

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