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azamat
3 years ago
6

Consider the following methods.public void modParams(int[] x, int[] y, String[] s){x[1] = 5;y = x;s[1] = new String("five");s =

new String[3];s[1] = new String("six");}public void print(){int[] a = {1, 2, 3};int[] b = {11, 22, 33};String[] s = {"one", "two", "three"};modParams(a, b, s);System.out.println(a[1] + " " + b[1] + " " + s[1]);}What is printed when print is called?a)2 22 twob)5 22 twoc)5 5 twod)5 22 fivee)5 5 six
Computers and Technology
1 answer:
skad [1K]3 years ago
5 0
I am not too happy to be a good man in my world but he is made me very very much and he is made me very very much and he is very much very good to him very much and he is very much very good to you very good and very much to be able for my kids with a little more money will not go back and you can do the greatest if he can be very much and you have no problem and then we do all the way that we are not the right answer but you have a question to do and you don’t have the right right answer the answer right back and he will not be very good I am very good and he is very very bad
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A cycle merchant allows 15% discount on the marked price of a bicycle and still he makes a profit
lions [1.4K]

Answer:

The program in Java is as follows:

public class Main{

public static void main(String[] args) {

 double discount_percent = 0.15;

 double discount_amount = 600;

 double profit = 0.20;

 double marked_price = discount_amount/discount_percent;

 double cost_price = marked_price/(1 + profit);

 System.out.println("Marked Price: "+marked_price);

 System.out.println("Cost Price: "+cost_price);

}}

Explanation:

For explanation purpose, let

MP \to Marked Price

\%D \to Percentage discount

D \to Discounted amount

\%P \to Percentage Profit

C \to Cost Price

The marked price (i.e. selling price) is calculated discount using:

MP = \frac{D}{\%D}

The derived formula of the cost price from percentage profit and Marked Price is:

C = \frac{M}{1 + \%P * 100}

So, the explanation is as follows:

The next three lines declare and initialize the given parameters

<em>  double discount_percent = 0.15;</em>

<em>  double discount_amount = 600;</em>

<em>  double profit = 0.20;</em>

Calculate marked price

 double marked_price = discount_amount/discount_percent;

Calculate cost price

 double cost_price = marked_price/(1 + profit);

Print marked price

 System.out.println("Marked Price: "+marked_price);

Print Cost price

 System.out.println("Cost Price: "+cost_price);

3 0
3 years ago
Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi
Kay [80]

Answer:

The algorithm is very similar to the algorithm of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.

Algorithm:

Let A = (a1, a2, . . . , an).

Function CountSigInv(A[1...n])

if n = 1 return 0; //base case

Let L := A[1...floor(n/2)]; // Get the first half of A

Let R := A[floor(n/2)+1...n]; // Get the second half of A

//Recurse on L. Return B, the sorted L,

//and x, the number of significant inversions in $L$

Let B, x := CountSigInv(L);

Let C, y := CountSigInv(R); //Do the counting of significant split inversions

Let i := 1;

Let j := 1;

Let z := 0;

// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;

//the normal merge-sort process i := 1; j := 1;

//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);

Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).

Explanation:

5 0
3 years ago
// This class calculates a waitperson's tip as 15% of the bill public class DebugThree1 { public static void main(String args[])
DENIUS [597]

I added a decimal format to keep all decimals within the hundredths place. I also changed the calcTip method to void and the argument to a double. Void means the method doesn't return anything and changing bill to type double let's us pass numbers with decimals to the calcTip method. I hope this helps!

Download txt
4 0
3 years ago
Most network cards contain a port that accepts a(n) ____, which looks similar to a telephone connector but is larger.
Vadim26 [7]
YOUR ANSWER IS -------- It accepts a RJ-45 connector
hope i helped you :).
take care
8 0
3 years ago
How can a PowerPoint user add a shadow to a table
damaskus [11]
Https://wordribbon.tips.net/T010192_Drop_Shadows_for_Tables.html
8 0
3 years ago
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