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brilliants [131]
3 years ago
8

The Java compiler does not check for an ArrayIndexOutorBoundsException during the compilation of a program containing arrays. O

True O False
Computers and Technology
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

TRUE

Explanation:

  • Let us first understand what is an ArrayIndexOutOfBounds Exception.
  • As the name itself suggests the index for the array has gone out of bound (permissible value) and an exception (anamoly) is resulted.
  • So, it throws an error.
  • That means if an array, Employee of size n is defined then the permissible elements are Employee[0] to Employee[n-1]. If any negative index or with the index is greater than n-1 is tried to access it throws an error saying ArrayIndexOutOfBounds Exception.
  • In java, during the compilation of the program the compiler doesn't check for the ArrayIndexOutOfBounds Exception.It checks during running the program.
  • So, it is called a Runtime Exception.
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Should you ever force a CPU into<br>its socket?​
tatyana61 [14]

Answer:

no you should not force a cpu into its socket.

Explanation: on an intel platform the pins are on the motherboard, therefore if you force it in it will damage the pins on the motherboard, and on AMD the pins are on the cpu itself so you can damage the extremely fragile pins on it, you can not shock your cpu however like the other answer.

7 0
3 years ago
In this lab, you complete a C++ program that swaps values stored in three int variables and determines maximum and minimum value
Sergio039 [100]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int first = 0,second = 0,third = 0;//defining integer variable  

int temp; //defining integer variable

const string SENTINEL = "done"; // defining a string variable as constant  

string repeat;// defining a string variable  

bool notDone = true; //defining bool variable

cout << "Enter first number: ";//print message

cin >> first;//input value

cout << "Enter second number: ";//print message

cin >> second;//input value

cout << "Enter third number: ";//print message

cin >> third;//input value

while(notDone == true)//defining a loop to check the value  

{

if(first > second)//use if to compare first and second value

{

int temp = first;//defining temp to hold first value

first = second;//holding second value in first variable

second = temp;//holding temp value in second variable

}

if(second > third)//use if to compare second and third value

{

int temp = second;//defining temp to hold second value

second = third;//holding second value in third variable

third = temp;//holding temp value in third variable

}

cout << "Smallest: " << first << endl;//print smallest value

cout << "Next smallest: " << second << endl;//print Next smallest value

cout << "Largest: " << third << endl;////print Largest value

cout << "Enter any letter to continue or done to quit: ";//print message

cin >> repeat;//holding string value

if (repeat == SENTINEL)

{

notDone = false;//holding bool value

}  

else //else block

{

cout << "Enter first number: ";//print message

cin >> first;//input value

cout << "Enter second number: ";//print message

cin >> second;//input value

cout << "Enter third number: ";//print message

cin >> third;//input value

}

return 0;

}

}

Output:

Please find the attached file.

Explanation:

  • Inside the main method Four integer variable "first, second, third, and temp" is declared in which first three variable is used for input value and temp is used to compare value.
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  • After input the value from the user-end a loop is declared that compare and swap value and print its value.

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3 years ago
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Answer:

vinranium

Explanation:

i watched the movie

IM SO SMART!!!!!!!!!!!!! UWU

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miskamm [114]
OSHA standards appear in the <span>Code of Federal Regulations (CFR) and are then broken down into Parts</span>
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zepelin [54]

Answer:

B

Explanation:

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4 0
3 years ago
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