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4 years ago

I need help with 37, 38, and 33

Mathematics

1 answer:

Sedbober [7]4 years ago

5 0

I just happened to notice that 32 is incorrect, it should be A
33. (21x+14)/5y+4y*5y/7(3x+2)
((21x+14)*5y)/((9y*7(3x+2)
((5(21x+14)/63(3x+2)
35(3x+2)/63(3x+2)
5/9 is the answer

37. |-3--7|+|-7--3|
|-3+7|+|-7+3|
|4|+|-4|
4+4=8
8 is the correct answer

38. 99999/1 you can 99999

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