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leonid [27]
3 years ago
8

I need help with 37, 38, and 33

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0
I just happened to notice that 32 is incorrect, it should be A
33.  (21x+14)/5y+4y*5y/7(3x+2)
((21x+14)*5y)/((9y*7(3x+2)
((5(21x+14)/63(3x+2)
35(3x+2)/63(3x+2)
5/9 is the answer

37. |-3--7|+|-7--3|
|-3+7|+|-7+3|
|4|+|-4|
4+4=8
8 is the correct answer

38. 99999/1 you can 99999
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Write the first three terms of the sequence n? + 3<br><br> Answer quick plzzz
Alborosie

Answer:

3, 6, 9

Step-by-step explanation:

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3 years ago
Two perpendicular lines intersect at the origin. If the slope of the first line is -1/2, what is the equation of the second line
Dovator [93]

bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes.

now, they both intersect at 0,0, namely they both pass through it, we know the slope of the first one, so

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{2}{1}\implies 2}}

so, we're really looking for the equation of a line whose slope is 2, and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} slope = m\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=2(x-0)\implies y=2x

5 0
3 years ago
QUESTION 1
Alexeev081 [22]

Answer:

1. 9

2. 10

Step-by-step explanation:

idk if those first 2 are right

6 0
3 years ago
(07.04 LC)What is the solution to the equation ax = 2?
Karo-lina-s [1.5K]

Answer:

x=12 .  

Step-by-step explanation:

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3 0
3 years ago
Subtract and simplify. Show work please!
ra1l [238]

1) Final expression: +7y^2-6y-17

2) Final expression: 21x^3-46x^2+59x-30

Step-by-step explanation:

1)

The first expression is

(-2y^2-11y-7)-(-9y^2-5y+10)

First, we remove the 2nd bracket by changing the sign of all the terms inside:

-2y^2-11y-7-+9y^2+5y-10

Now we group the terms with same degree together:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)

Now we solve the expression in each brackets:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17

So, this is the final expression.

2)

The second expression is

(7x-6)(3x^2-4x+5)

We apply the distributive property, so we rewrite the expression as follows:

(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)

Solving both brackets,

7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30

Now we group terms of same degree together:

21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30

And solving each bracket,

21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0
3 years ago
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