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3 years ago

What is the volume of a cone with a base of 10 and height of 9

Mathematics

1 answer:

Leto [7]3 years ago

5 0

The formula being used is V= $\pi$ r^2(h/3)

V≈235

V=235.62 to be approximate

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Find the circumference of the given circle 11 ft

nasty-shy [4]

Answer:

69.12

Step-by-step explanation:

5 0

3 years ago

Given a linear equation in the form y=mx+b, what are the values of the slope and y-intercept of the equation?(1 point) The slope

slamgirl [31]

Answer:

The slope is m, and the y-intercept is b.

Step-by-step explanation:

What ever is attached to the x is the slope. The y-intercept is the b because it has a 0 on the x axis and a number on the y axis.

7 0

3 years ago

keith bought a belt for 9$ and a shirt that cost 4 times as much as the belt. he then had 10 dollars. how much money did Keith h

netineya [11]

9 times 4 is $36 which is the price of the belt
$36 + $9 = 45
$45 + $ 10 = 55 so
<u>Keith had $55 dollars before he bought the shirt and the belt
</u>

7 0

3 years ago

Classify the following triangle. Check all that apply

Pavel [41]

Step-by-step explanation:

it's a right angled triangle

it's also a scalene triangle because not all sides are equal

3 0

3 years ago

Read 2 more answers

Use the set of data to calculate the measures that follow.

zepelin [54]

Answer:

<h3>Mean=3.5</h3><h3>Median=3.5</h3><h3>Range=6</h3><h3>Interquartile=1</h3>

Step-by-step explanation:

Given set of data is 0, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6

<h3>To find Mean , Median , Range and Interquartile range :</h3>

First finding Mean

$Mean=\frac{sum of the observations}{number of observations}$
$=\frac{0+2+3+3+3+3+3+4+4+4+4+5+5+6}{14}$
$=\frac{49}{14}$
$=\frac{7}{2}$
$=3.5$

<h3>Therefore Mean=3.5</h3><h3>Median:</h3>

Since the number of observations is even, so the meadian becomes
$Median=\frac{sum of the two mid terms}{2}$
$=\frac{3+4}{2}$
$=\frac{7}{2}$
$=3.5$

<h3>Therefore Median=3.5</h3><h3>Range:</h3>

Range=greatest value-least value
In the given observations we have greatest value is 6 and least value is 0
Therefore Range=6-0

<h3>Therefore Range=6</h3><h3>Interquartile:</h3>

From the observations we have $Q_1=3$ and $Q_3=4$
$Interquartile=Q_3-Q_1$
$=4-3$

<h3>Therefore Interquartile=1</h3><h3 />

3 0

3 years ago

Read 2 more answers