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vredina [299]
3 years ago
7

The distance (in miles) traveled by a cyclist is given by d(t) = 5t, where t is the time in seconds. The domain of the function

includes
a- all real numbers that are perfect squares
b- all positive real numbers and zero
c- all real numbers other than 5
d- all real numbers
Mathematics
2 answers:
Ivahew [28]3 years ago
5 0
Answer: option b - all positive real numbers and zero.

The only restriction is that the time cannot be negative (and of course, it has to be a real number, not imaginary).
ASHA 777 [7]3 years ago
4 0

Answer:

b. All positive  real numbers and zero

Step-by-step explanation:

We are given that  the distance traveled by a cyclist is given by

d(t)=5t

Where t=Time in seconds

We have to find the domain  of the function .

We know that distance is always positive.

Given function is linear function .

We know that domain of linear function is set of all real numbers.

But t is time and t is always positive.

Therefore, domain of function includes  all positive real numbers and zero.

Answer: b. All  positive real numbers and zero.

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What is the slope of the line through the point A(-3,4) and B(2,-1)
Best answer
A -1
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D - 1/3
8 0
3 years ago
Find the slope of the line on the graph. Write your answer as a fraction or a whole number, not mixed number or decimal.
Vesna [10]

Answer:

<em>The slope is:</em>

m=-\frac{3}{2}

Step-by-step explanation:

The slope m of a line is calculated using the following formula

m=\frac{y_2-y_1}{x_2-x_1}

Where the points (x_1, y_1) and (x_2, y_2)  are two points belonging to the straight line

Notice in the graph that the line passes through the points

(0, 2) and (2, -1)

Then the slope is:

m=\frac{-1-2}{2-0}

m=\frac{-3}{2}

4 0
3 years ago
6-√8 divide √2-1
agasfer [191]

Answer:

4\sqrt{2}  +2

Step-by-step explanation:

\frac{6-\sqrt{8}}{\sqrt{2}-1}

=\frac{6-\sqrt{8}}{\sqrt{2}-1} ×\frac{\sqrt{2}+1}{\sqrt{2}+1}

=\frac{(6-\sqrt{8})(\sqrt{2}+1)}{2-1}

=6\sqrt{2} + 6 -\sqrt{8}\sqrt{2} - \sqrt{8}

=6\sqrt{2} + 6 - 4 - \sqrt{8}

=6\sqrt{2} + 2 - \sqrt{8}

=6\sqrt{2} + 2 - 2

=4\sqrt{2}  +2

for \sqrt{8} = 2\sqrt{2} ,

\sqrt{8} = \sqrt{2*2*2}

     = (\sqrt{2})^2 × \sqrt{2}

     =2 ×\sqrt{2}

5 0
3 years ago
In 1980, the median age of the U.S. population was 30.0; in 2000, the median age was 35.3.
miss Akunina [59]

Answer:

y = 0.265x - 494.7

Step-by-step explanation:

Let median age be represent by 'a' and time be represent by 't'

In 1980, median age is given 30

which means that

a₁ = 30

t₁ = 1980

In 2000, the median age is given 35.3

which means that.

a₂ = 35.3

t₂ = 2000

The slope 'm' of the linear equation can be found by:

m = (a₂ - a₁) /(t₂ - t₁)

m = (35.3 - 30)/(2000-1980)

m = 0.265

General form of linear equation is given by:

y = mx + c

y = 0.265x +c

Substitute point (1980,30) in the equation.

30 = 0.265(1980) + c

c = -494.7

Hence the the linear equation can be written as:

y = mx + c

y = 0.265x - 494.7

4 0
3 years ago
Through: (-3,0), perp. to y = 3x - 1
Marrrta [24]

Answer:

y=-\dfrac{1}{3}x-1

Step-by-step explanation:

<u>Given: </u>

line y=3x-1

point (-3,0)

<u>Write:</u> equation of the line that is perpendicular to the given and passes through the point (-3,0)

<u>Solution:</u>

The slope of the given line is m=3

If m_1 is the slope of perpendicular line, then

m\cdot m_1=-1\\ \\3m_1=-1\\ \\m_1=-\dfrac{1}{3}

So, the equation of the needed line is y=-\dfrac{1}{3}x+b.

Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:

0=-\dfrac{1}{3}\cdot (-3)+b\\ \\0=1+b\\ \\b=-1\\ \\y=-\dfrac{1}{3}x-1

7 0
3 years ago
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