Answer:
The option A,D and E are correct.
Step-by-step explanation:
Given: 2x^3-250x^2
Factor : 2x^2(x-125)
So, GCF = 2x^2
Now a = 1 and b= 5
we know that a^3-b^3 = (a-b)(a^2+ab+b^2)
(x)^3 - (5)^3 = (x-5)(x^2+5x+25)
So, the option A,D and E are correct.
-3x - y = -17
4x + 2y = 20
multiply one part of the equation so that we can be able to use the process of elimination.
(-3x - y = -17)2
4x + 2y = 20
Now we have:
-6x -2y = - 34
4x+2y= 20
------------------------
-2x = -14
Divide -2 on both sides.
-2x = -14
/-2 /-2
x = -7.
=============================================
To solve for y, we just have to substitute the value of x to any of the equation given above, that we feel comfortable with. And I'm going to choose this equation: 4x + 2y = 20
4x + 2y = 20
4(-7) + 2y = 20
-28 + 2y = 20
Add 28 on both sides
-28 + 2y = 20
+28 +28
---------------------
2y = 48
/2 /2
y = 24.
The last thing you would do is to check if the answers is correct.
All you have to do is plug in the values of x and y into both equations and see if they equal to one another.
You may have to do this by yourself :P
Anyways, if you have any questions about this topic, feel free to PM me or any other users interested. Thank you for being part of Brainly! Have a nice day!
Answer:
3 = k
Step-by-step explanation:
Step 1: Write equation
4 - 7k = 1 - 6k
Step 2: Solve for <em>k</em>
<u>Add 7k on both sides:</u> 4 = 1 + k
<u>Subtract 1 on both sides:</u> 3 = k
The standard form of a quadratic function is y = 3/2x² + 17/2x - 7
<h3>How to determine the
quadratic equation?</h3>
From the question, the points on the quadratic equation are given as
(2,4), (3,5) and (4,3)
The standard form of a quadratic equation is represented as
y = ax² + bx + c
So, we have
Point (2,4):
4a + 2b + c = 4
Point (3,5):
9a + 3b + c = 5
Point (4,3):
16a + 4b + c = 3
Solving using an online calculator. we have
a = 3/2, b = 17/2 and c = -7
Substitute a = 3/2, b = 17/2 and c = -7 in y = ax² + bx + c
y = 3/2x² + 17/2x - 7
Hence, the equation is y = 3/2x² + 17/2x - 7
Read more about quadratic equation at
brainly.com/question/1214333
#SPJ1