The answer is c. Anaphase I separates homologous chromosomes and anaphase II separates sister chromatids into daughter cells.
Meiosis is a cell division which results in the reduction of chromosome number by half (from diploid to haploid) in daughter cells. It consists of meiosis I and meiosis II.
In anaphase I, the sister chromatids separate from each other to the opposite sides of the cells. In meiosis I there are 46 chromosomes in duplicates which are present as pairs of sister chromatids. When comes to separation, homologous chromosomes separates only, but not sister chromatids. Homologous chromosomes are present only in meiosis I.
In anaphase II, since the cell is haploid, there are 23 chromosomes in duplicates, which are present as sister chromatids. So, in this phase, sister chromatids are those who separates.
Answer:
Option B, Rr pp × rr Pp
Explanation:
Given
Walnut Comb is produces when one dominant allele R is present at one gene locus and at least one dominant allele P is present at a second gene locus - R* P*
Rose Comb - at least one dominant allele is present at the first locus and two recessive alleles are present at the second locus - R* pp
Pea comb - two recessive alleles are present at the first locus and at least one dominant allele is present at the second - rr P*
Single comb - two recessive alleles are present at the first and the second locus - rrpp
Parent are rose combed and pea combed
For being rose genotype must be R* pp
and for being pea combed genotype must be rr P*
Rr pp x rr Pp
will produce
Walnut comb with genotype Rr Pp
Single comb with genotype rrpp
and pea comb with genotype rrPp
Hence, option B is correct
Modern classification, otherwise known as taxonomy, was invented so as to have a single system used throughout the entire world in understanding different types of beings in existence. This way you avoid having different names for same things.
Earthquakes because they shift the plates.
