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Alchen [17]
3 years ago
15

What is the solution for the question with the shaded circle?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
6 0
<span>
5*n+(3/4)*n = 2 // - 2

5*n+(3/4)*n-2 = 0

23/4*n-2 = 0 // + 2

23/4*n = 2 // : 23/4

n = 2/23/4

n = 8/23
</span> 
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Which of the following are solutions to the equation below?
Natasha2012 [34]
Both A and C would be solutions to the equation.

In order to solve for this you must first get the equation equal to 0. 

2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0

Now knowing this we can use the coefficients of each one in descending order of power as a, b and c. 

a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)

Now we can plug these values into the quadratic equation. 

\frac{-b +/- \sqrt{b^{2} - 4ac } }{2a}

\frac{-5 +/- \sqrt{5^{2} - 4(2)(2) } }{2(2)}

\frac{-5 +/- \sqrt{9} }{4}

\frac{-5 +/- 3 }{4}

\frac{-5 + 3 }{4} or -1/2 for the first answer

\frac{-5 - 3 }{4} or -2 for the second answer

5 0
3 years ago
HELP SOMEONE PLEASE!!!!!!!!!!!!!!!!!!!
omeli [17]

Answer:

3/10

Step-by-step explanation:

The question asks for the probability of finding 4 or more, so first, you must add up all of the teenagers that have 4 or more shoes. Both the 4 and 5 categories fit, so add 20 and 10. Then, find the total number of people in the sample size. Overall, 100 teenagers are represented. Finally, put the number of people that have 4 or more shoes, 30, over the sample size, 100. This equals 30/100 which should be simplified to 3/10.

6 0
3 years ago
Suppose we roll a fair six-sided die and sum the values obtained on each roll, stopping once our sum exceeds 307. Approximate th
SOVA2 [1]

Answer:

There is a probability of P=0.94 that at least 81 rolls are needed to get the sum of 307.

Step-by-step explanation:

The roll of a six-sided die sum has this parameters:

Mean: 3.5

Standard deviation: 1.7

If the die is rolled 81 times, the distribution of the sum of the 81 rolls will have the following parameters:

\mu=n*M=81*3.5=283.5\\\\\sigma=\sqrt{n}s=\sqrt{81}*1.7=9*1.7=15.3

Note: the variance of the sum of random variables is equal to the sum of the variance of the individual variables.

Then, we can calculate the probabilties that the sum of 81 rolls is lower than 307.

z=\frac{x-\mu}{\sigma}=\frac{307-283.5}{15.3}=  \frac{23.5}{15.3}= 1.536\\\\\\P(x

There is 94% of chances that the sum of 81 rolls is lower than 307, so there is a probability of P=0.94 that at least 81 rolls are needed to get the sum of 307.

5 0
3 years ago
George is reading a book. After 3 hours he has read 90 pages, and at the end of 5 hours he has read 180 pages. What is the avera
Andrew [12]

Answer:

6/1

Step-by-step explanation:

He read 90 pages in 3 hours so it's 30/1 pages/hour

Then he reads 180 pages in 5 hours so it's 36/1 pages /hours

the rate of difference is 30/1 ÷ 36/1 is 6 pages per hour

8 0
3 years ago
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Klio2033 [76]

Answer:

doing well

Step-by-step explanation:

the reason i doing well is because nice people are giving me answers to questions that i need help with.

7 0
3 years ago
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