Answer:
n=0
Step-by-step explanation:
See pictures
Hope this helps ^-^
Answer:
x = - 12, 3
Step-by-step explanation:
By tangent secant theorem:

Answer:
Option D. -1 and 0
Step-by-step explanation:
Since
(density = mass/volume), we can get the mass/weight of the liquid by integrating the density
over the interior of the tank. This is done with the integral

which is more readily computed in cylindrical coordinates as

Cos ( 390)
- 4 cot (-45)
Csc (60)
Hope this helps