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Alchen [17]
2 years ago
11

61 divided by 3427?

Mathematics
1 answer:
katrin2010 [14]2 years ago
8 0
61 / 3427= 0.01779982. (rounds up to 0.02 if rounded by hundredths)
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A 400 foot rope is extended from the ground to the top of a building. The building is 35 ft tall. What is the angle made by the
velikii [3]

Answer:

The angle is 5.0^{0}.

Step-by-step explanation:

The building is 35 feet tall, and the rope is 400 feet long.Applying the trigonometric function, we have;

Sin θ = \frac{opposite}{hypotenuse}

The height of the building represents the opposite side, while the length of the rope represents the hypotenuse. Thus;

Sin θ = \frac{35}{400}

Sin θ = 0.0875

θ = Sin^{-1} 0.0875

  = 5.02^{0}

The angle made by the rope with respect to the ground is approximately 5.0^{0}.

3 0
3 years ago
7+3x-12x=3x+1 is it Infinitely many solutions, one solution, or no solutions with steps please
alisha [4.7K]

Answer:

  • One solution

Step-by-step explanation:

  • 7 + 3x - 12x = 3x + 1
  • 7 - 9x = 3x + 1
  • 3x + 9x = 7 - 1
  • 12x = 6
  • x = 6/12
  • x = 1/2

It has one solution

3 0
3 years ago
What is the constant of variation for the relationship f(x)=30x
elixir [45]
B)30.................
3 0
3 years ago
Read 2 more answers
a kittens heartbeat can be as fast as 240 beats per minute . to find the number of times a kittens heart beats in 30 seconds , A
Alina [70]
I do not agree. If you divide 240 by 30, it would be 8 heartbeats, which is absurd. It's impossible for something to survive with 8 heartbeats per 30 seconds.
In order to get the CORRECT answer, divide 240 by 60 seconds.
This would give you 4 heartbeats per second.
Then, multiply it by 30 seconds, which would give you 120 heartbeats.

CORRECT answer: 120

5 0
3 years ago
If m∠OZQ = 125 and m∠OZP = 62, what is m∠PZQ
const2013 [10]

Answer:

<h2>               63° or  173°</h2>

Step-by-step explanation:

You didn't specify where the point P is so there are two posibilites:

1.

P₁Z is dividing angle OZQ

then:

      m∠P₁ZQ = m∠OZQ - m∠OZP₁ = 125° - 62° = 63°

2.

P₂Z is outside angle OZQ

then

    m∠P₂ZQ = 360° - (m∠OZQ + m∠OZP₂) = 360° - (125° + 62°) = 173°

5 0
3 years ago
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