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xxMikexx [17]
3 years ago
7

All possible outcomes for flipping a coin three times are listed below: (H = heads up, T = tails up) {HHH, THH, HTH, HHT, TTH, T

HT, HTT, TTT} What is the probability of obtaining at least 1 heads?
Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0

Answer:

7 out of 8

Step-by-step explanation:

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The sum of 6 and the product of 8 and x" into mathematical expression
Inga [223]

Answer:

6=8x

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the simplified form of this expression?<br> (7 + x) + (487-4-1)
tamaranim1 [39]

Answer:

Step-by-step explanation:

( 7 + ) + ( 4 8 7 − 4 − 1 ) (x+ 7 ) + (4 8 7− 4 − 1 )

( + 7 ) + 4 8 2 x+ 7 + 4 8 2

Add numbers

+ 48 9

Answer is x+489

3 0
3 years ago
Write out the sample space for the given experiment. Use the following letters to indicate each choice: W for white, Y for yello
allochka39001 [22]

Answer:

S={WG, WE, WM, YG, YE, YM, BG, BE, BM}

Step-by-step explanation:

There are three possible color choices for the game room (White, Yellow or Blue), and three possible choices for the entertainment center (Gray, Ebony or Maple). This means that there are 9 possible outcomes, therefore, the sample space for the experiment is:

S={WG, WE, WM, YG, YE, YM, BG, BE, BM}

4 0
3 years ago
Which of these strategies would eliminate a variable in the system of equations?
KATRIN_1 [288]
Answer: A and B


Explanation: I’ll use A as an example. When you multiply the bottom equation by -3/2, the equation becomes: -9x+6y=-3. Then, proceed to add the equations. Look at X and Y in both equations: do the Y variables in both equations equal to 0 when added together? Yes, because -6y+6y=0! Therefore, you can eliminate y in these two equations.




Hope that’s helps シ
6 0
3 years ago
(5 points) An urn contains two blue balls denoted by B1 and B2, and three white balls denoted by W1, W2 and W3. One ball is draw
never [62]

Answer:

The probability of the event that first ball that is drawn is blue  is \frac 25.

Step-by-step explanation:

Probability:

If S is is an sample space in which all outcomes are equally likely and E is an event in S, then the probability of E,denoted P(E) is

P(E)=\frac{\textrm{The number of outcomes E}}{\textrm{The total number outcomes of S}}

Given that,

An urn contains two balls B₁ and  B₂ which are blue in color and W₁,W₂ and W₃ which are white in color.

Total number of ball =(2+3) =5

The number ways of selection 2 ball out of 5 ball is

=5²

=25

Total outcomes = 25

List of all outcomes in the event that the first ball that is drawn is blue are

B₁B₁ , B₁B₂ , B₁W₁ , B₁W₂ , B₁W₃ , B₂B₁ , B₂B₂ ,  B₂W₁ , B₂W₂ , B₂W₃

The number of event that the first ball that is drawn is blue is

=10.

The probability of the event that first ball that is drawn is blue  is

=\frac{10}{25}

=\frac25

3 0
4 years ago
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