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MrRissso [65]
3 years ago
10

8-2b=-2/3(12b+6) solve

Mathematics
2 answers:
Natalija [7]3 years ago
7 0
We have to mutiply factor -2/3 times every agument from the parenthesis.
8-2b=- \frac{2*12b}{3}- \frac{2*6}{3}   \\ 8-2b= -8b-4 \\     /+8b
8+6b=-4         /-8
6b=-12         /:6
b=-2 - its the answer
pishuonlain [190]3 years ago
6 0
8-2b=-\frac { 2 }{ 3 } \left( 12b+6 \right) \\ \\ 8-2b=-\frac { 2 }{ 3 } \cdot 12b-\frac { 2 }{ 3 } \cdot 6\\ \\ 8-2b=-\frac { 24 }{ 3 } b-\frac { 12 }{ 3 } \\ \\ 8-2b=-8b-4\\ \\ -2b+8b=-4-8\\ \\ 6b=-12\\ \\ b=\frac { \left( -12 \right)  }{ 6 } \\ \\ \therefore \quad b=-2
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Answer:

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Step-by-step explanation:

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Hello,

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8 0
3 years ago
Read 2 more answers
Set up a linear system and solve.
liubo4ka [24]

Answer:

The two integers are 23 and 12

Step-by-step explanation:

Let the two integers be f and g

Let f be the biggest and g the smallest integer

From the first statement, the sum of the two integers is 35 i.e

f + g = 35. (1)

From second statement, we were told that when the smaller integer is subtracted from twice the larger, the result is 34 i.e

2f — g = 34. (2)

Now we'll solve by elimination method as follows:

Add equation (2) and (1) together:

2f — g = 34

+ f + g = 35

3f = 69

Divide both side by the coefficient of f i.e 3

f = 69/3

f = 23

Substituting the value of f into equation(1)

f + g = 35

23 + g = 35

Collect like terms

g = 35 — 23

g = 12

The two integers are 23 and 12

4 0
3 years ago
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