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MrRissso [65]
3 years ago
10

8-2b=-2/3(12b+6) solve

Mathematics
2 answers:
Natalija [7]3 years ago
7 0
We have to mutiply factor -2/3 times every agument from the parenthesis.
8-2b=- \frac{2*12b}{3}- \frac{2*6}{3}   \\ 8-2b= -8b-4 \\     /+8b
8+6b=-4         /-8
6b=-12         /:6
b=-2 - its the answer
pishuonlain [190]3 years ago
6 0
8-2b=-\frac { 2 }{ 3 } \left( 12b+6 \right) \\ \\ 8-2b=-\frac { 2 }{ 3 } \cdot 12b-\frac { 2 }{ 3 } \cdot 6\\ \\ 8-2b=-\frac { 24 }{ 3 } b-\frac { 12 }{ 3 } \\ \\ 8-2b=-8b-4\\ \\ -2b+8b=-4-8\\ \\ 6b=-12\\ \\ b=\frac { \left( -12 \right)  }{ 6 } \\ \\ \therefore \quad b=-2
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Step 1:

a) Write the quadratic model

a = -15.64

b = -1.24

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\begin{gathered} P(t)=-15.64t^2\text{ - 1.24t + 5.2}3 \\ =\text{ -15.64 }\times0.3^2\text{ - 1.24}\times\text{ 0.3 + 5.2}3 \\ =\text{ -1.4076 - 0.372 + }5.23 \\ =\text{ 3.45} \end{gathered}

c) t = 0.52 seconds

\begin{gathered} p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ =\text{ -15.64}\times0.52^2\text{ - 1.23}\times0.52\text{ + 5.23} \\ =\text{ -4.23 - 0.64 + 5.23} \\ =\text{ 0.36} \end{gathered}

d) 0.30 is more likely to be relaible.

e)

\begin{gathered} p(t)\text{ = 1} \\ p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ 1=-15.64t^2\text{ - 1.23t + 5.23} \\ -15.64t^2\text{ - 1.23t + 4.23 = 0} \\ t\text{ = 0.48222} \\ \text{t = 0.48 seconds} \end{gathered}

5 0
1 year ago
How would you write odds in favor?
Andrews [41]

Answer: Odds in favor = Number of successes: Number of failures

Step-by-step explanation:

Example

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The odds are 5:8

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The answer is 114 which is the first answer which is A

Step-by-step explanation:

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