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3 years ago

HELP PLEASE

Mathematics

2 answers:

DerKrebs [107]3 years ago

6 0

3 terms
5x, 2x^2, -8

2nd degree
highest exponent is 2

2nd degree polynomial (3 terms)

just olya [345]3 years ago

4 0

Answer:

Option C. is the answer.

Step-by-step explanation:

We have to classify the given expression (5x + 2x² - 8).

This expression has total number of terms = 3

So the expression is a trinomial.

Highest degree term in this expression is 2x², which is a second degree term.

So the expression will be defined as second degree.

In total, the expression is second degree trinomial.

Option C. second degree trinomial is the answer.

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Pippi sold ten more cups of lemonade that cups of iced tea. She sold 120 cups in all. How many cups of lemonade did she sell?

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Answer:

65 cups

Step-by-step explanation:

If she sold 10 more cups of lemonade than tea and sold 120 cups total. I first would subtract 10 cups from 120 =110. then I divide 110 /2 = 55 cups

The 55 cups makes it equal then I add the 10 cups back to the Lemonade to get 55+10 = 65

So your answer would be 65 cups of lemonade

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3 years ago

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3 years ago

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.

marishachu [46]

Answer:

$\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

Step-by-step explanation:

We have been given the function

$f(x)=-2x^2+4x^3+3x^2+18$

From the rational zeros theorem, we have

$\text{Possible rational zeros}=\pm\frac{\text{Factors of constant term}}{\text{Factors of leading coefficient}}$

From the given function,

Leading coefficient = 2

Factors of 2 are 1,2

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Factors of constant term = 1, 2, 3, 6, 9, 18

Hence, we have

$\text{Possible rational zeros}=\pm\frac{1,2,3,6,9,18}{1,2}\\\\\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

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3 years ago

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3 years ago

Help

Art [367]

$\huge\fbox{Answer ☘}$

$\bold{3( \frac{27}{8} ) {}^{ \frac{2}{3} \times - 1} = 2( \frac{32}{243} ) {}^{2x} }\\ \\3(( \frac{3}{2} ) {}^{3} ) {}^{ \frac{2}{3} \times - 1 } = 2(( \frac{2}{3} ) {}^{5} ) {}^{2x} \\\\ 3( \frac{3}{2} ) {}^{2 \times - 1} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{2}{3} ) {}^{2} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{4}{9} ) = 2( \frac{4}{9} ) {}^{5x} \\\\\bold\pink{ comparing \: powers }\\\\5x = 1 \\\\ \bold\blue{x = \frac{1}{5} }$

hope helpful~

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2 years ago