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trasher [3.6K]
4 years ago
9

If you flip three fair coins, what is the probability that the first two flips will both be heads, and the third flip will be ei

ther heads or tails?
Mathematics
2 answers:
Sveta_85 [38]4 years ago
5 0
25%. With a 50% chance of it landing heads the first time, you need to multiply it by the percentage that you have that it will land on heads again, which is 50. 50% of 50 is 25, and then having it land on either heads or tails for the third time is guaranteed, so multiply that probability (100%) by the previous 25% which ends up being simply 25%
slava [35]4 years ago
3 0

Answer:

It ain’t 25% I put that and it said it was incorrect!!

Step-by-step explanation:

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Help would really be appreciated. The question is in the picture.
Vikentia [17]
|-11+8|=|-3|=3. Plug in f(-11)
4 0
3 years ago
Subtract and simplify. Show work please!
ra1l [238]

1) Final expression: +7y^2-6y-17

2) Final expression: 21x^3-46x^2+59x-30

Step-by-step explanation:

1)

The first expression is

(-2y^2-11y-7)-(-9y^2-5y+10)

First, we remove the 2nd bracket by changing the sign of all the terms inside:

-2y^2-11y-7-+9y^2+5y-10

Now we group the terms with same degree together:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)

Now we solve the expression in each brackets:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17

So, this is the final expression.

2)

The second expression is

(7x-6)(3x^2-4x+5)

We apply the distributive property, so we rewrite the expression as follows:

(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)

Solving both brackets,

7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30

Now we group terms of same degree together:

21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30

And solving each bracket,

21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0
3 years ago
4.0 divided by 0.02=
elena-14-01-66 [18.8K]

Answer:

200

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
The sum of two numbers is 48. If one third of one number is 5 greater than one sixth of another number, which of the following i
lubasha [3.4K]
<span>The sum of two numbers is 48.
a + b = 48
;
If one third of one number is 5 greater than one sixth of another number,
a = b + 5
multiply both sides by 6, cancel the fractions
2a = b + 30
2a - b = 30
</span><span>use elimination to solve this
a + b = 48
2a - b =30
-------------Addition eliminates b, find a
3a = 78
a = 
a = 26
then
26 + b = 48
b = 48 - 26

b = 22</span>
5 0
3 years ago
How many times does 32 go into 204
jeka94
This question have 2 different answer depending on what law he is stating in this problem
Solution 1
=> 204 / 32 = 6.38 times did 32 goes to 204.
Solution 2
=> 204 - 32 = 172
=> 172 / 32 = 5.38
=> 5.38 * 100% - 538%
6 0
3 years ago
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